ABPersonViewController不支持iOS 7.0及更高版本中的子类

Question

is there any best way to listout Property of Contact in detail? like it is working in IOS 6.1 and earlier Version.

//
//  ABPersonViewController.h
//  AddressBookUI
//
//  Copyright (c) 2010 Apple Inc. All rights reserved.
//

#import <UIKit/UIViewController.h>
#import <AddressBook/AddressBook.h>

@interface ABPersonViewController : UIViewController <UIViewControllerRestoration>

// ABPersonViewController does not support subclassing in iOS 7.0 and later. A nil instance will be returned.

Answer 1

我找到了一个解决方案:请参阅来源

有一些不推荐的函数，但是我们可以通过在"ABContactsHelper“类中替换下面的函数来解决它

+ (ABAddressBookRef) addressBook
{
#ifdef __IPHONE_6_0
    return ABAddressBookCreateWithOptions(NULL, NULL);
#else
    return ABAddressBookCreate();
#endif
}

在调用"ABAddressBookCreate()“的地方使用它。喜欢

ABAddressBookRef addressBook = [ABContactsHelper addressBook];