我有两个包含键/值对的数组。
{
"containerOne": [{
"Id": 1,
"Title": "TitleOne",
"Responsibility": "ValueOne"
}, {
"Id": 2,
"Title": "TitleTwo",
"Responsibility": "ValueTwo"
}]
}
{
"containerTwo": [{
"Id": 1,
"Title": "TitleOne",
"Responsibility": null
}, {
"Id": 2,
"Title": "TitleTwo",
"Responsibility": "null
}
]
}我想比较这两个数组并比较每个容器的标题。如果标题匹配,那么我想将责任值从containerOne复制到containerTwo。ID将不匹配,因此可以排除。只有标题是一致的。
请问最有效的方法是什么?]
谢谢
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编辑
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仔细看一下数组,返回的数据有一个细微的差别:
{
"AMLookupTasksList":
[
{
"Id":1,
"Title":"Create and Maintain an Onboarding Document",
"Responsibility":"1. Onboarding|f101ccf1-c7d5-42e7-ba8f-48e88ac90a3d"
},
{
"Id":2,
"Title":"Execute Onboarding for New Consultants",
"Responsibility":"1. Onboarding|f101ccf1-c7d5-42e7-ba8f-48e88ac90a3d"
}
]}
{
"AMTasksList":
[
{
"Id":4,
"Title":
{
"$M_1":13,"$c_1":"Create and Maintain an Onboarding Document"
},
"Responsibility":null
},
{
"Id":17,
"Title":
{
"$M_1":12,"$c_1":"Execute Onboarding for New Consultants"
},
"Responsibility":null
}
]}
是否有额外的循环以获得第二个数组中的Title值?
发布于 2013-09-19 21:00:41
这可能有点过分,但它忽略了序列,并在每个对象中进行了查找。我必须在您的对象中修复一些语法,但是我包括了:命名对象并从其中一个空值中删除一个引号。
var obj1 = {
"containerOne": [{
"Id": 1,
"Title": "TitleOne",
"Responsibility": "ValueOne"
}, {
"Id": 2,
"Title": "TitleTwo",
"Responsibility": "ValueTwo"
}]
};
var obj2 = {
"containerTwo": [{
"Id": 1,
"Title": "TitleOne",
"Responsibility": null
}, {
"Id": 2,
"Title": "TitleTwo",
"Responsibility": null
}]
};现在代码:
// lookup for first object:
var lookup = {};
// create referece to list above and use it everywhere
lookup.list = obj1;
for (var i = 0, len = lookup.list.containerOne.length; i < len; i++) {
lookup[lookup.list.containerOne[i].Title] = lookup.list.containerOne[i];
}
// lookup for second object
var otherLookup = {};
otherLookup.list = obj2;
for (var i = 0, len = otherLookup.list.containerTwo.length; i < len; i++) {
otherLookup[otherLookup.list.containerTwo[i].Title] = otherLookup.list.containerTwo[i];
}
// copy value for Responsibility from first to second on each matched in second.
var i = 0;
var len = lookup.list.containerOne.length;
for (i; i < len; i++) {
// looks up value from second list in the first one and if found, copies
if (lookup[otherLookup.list.containerTwo[i].Title]) {
otherLookup.list.containerTwo[i].Responsibility = lookup[otherLookup.list.containerTwo[i].Title].Responsibility;
}
}
// alerts new value using lookup
alert(otherLookup["TitleOne"].Responsibility);编辑新结构,但同样的答案实际上是:
var obj1 = {
"AMLookupTasksList": [{
"Id": 1,
"Title": "Create and Maintain an Onboarding Document",
"Responsibility": "1. Onboarding|f101ccf1-c7d5-42e7-ba8f-48e88ac90a3d"
}, {
"Id": 2,
"Title": "Execute Onboarding for New Consultants",
"Responsibility": "1. Onboarding|f101ccf1-c7d5-42e7-ba8f-48e88ac90a3d"
}]
};
var obj2 = {
"AMTasksList": [{
"Id": 4,
"Title": {
"$M_1": 13,
"$c_1": "Create and Maintain an Onboarding Document"
},
"Responsibility": null
}, {
"Id": 17,
"Title": {
"$M_1": 12,
"$c_1": "Execute Onboarding for New Consultants"
},
"Responsibility": null
}]
};
var lookup = {};
// create refernece to list above and use it everywhere
lookup.list = obj1;
for (var i = 0, len = lookup.list.AMLookupTasksList.length; i < len; i++) {
lookup[lookup.list.AMLookupTasksList[i].Title] = lookup.list.AMLookupTasksList[i];
}
var otherLookup = {};
otherLookup.list = obj2;
for (var i = 0, len = otherLookup.list.AMTasksList.length; i < len; i++) {
otherLookup[otherLookup.list.AMTasksList[i].Title.$c_1] = otherLookup.list.AMTasksList[i];
}
// copy value for Responsibility from first to second
var i = 0;
var len = otherLookup.list.AMTasksList.length;
for (i; i < len; i++) {
if (lookup[otherLookup.list.AMTasksList[i].Title.$c_1]) {
otherLookup.list.AMTasksList[i].Responsibility = lookup[otherLookup.list.AMTasksList[i].Title.$c_1].Responsibility;
}
}
alert(otherLookup["Create and Maintain an Onboarding Document"].Responsibility);第二个答案:http://jsfiddle.net/n22V8/
发布于 2013-09-19 19:51:16
首先,从containerTwo创建一个字典
var c2dict = {};
var c2i = containerTwo.innerContainer;
for (var i = 0; i < c2i.length; i++) {
c2dict[c2i[i].Title] = c2i[i];
}现在使用此方法在标题匹配时复制属性:
var c1i = containerOne.innerContainer;
for (var i = 0; i < c1i.length; i++) {
if (c2dict[c1i[i].Title]) {
c2dict[c1i[i].Title].Property = c1i[i].Property;
}
}发布于 2013-09-19 19:45:26
您应该比较属性并将其设置为:
containerOne.innerContainer.forEach(function (element,index) {
containerTwo.innerContainer.forEach(function (element2,index2) {
if (element.Title === element2.Title && element.Property != element2.Property) {
element2.Property = element.Property;
}
});
});https://stackoverflow.com/questions/18903482
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