动态内容切换

Question

我正在开发jquery，并试图在动态内容上使用slideToggle，但我无法弥补幻灯片。怎样才能使它正常工作呢？我会给你提供http://jsfiddle.net/P3WaC/

<li class="pull-right">
<div class="text-righ padding-right">
    <div class="chart">My cart (<span class="item_cart">3</span>)</div>
    <button class="btn btn-warning">CHECKOUT</button>
    <input type="text" class="input-large light-panel active-tab-search" placeholder="Search rewards">
</div>
<div id="cart-info" style="display: none;">
    <div id="each-2" class="shopp" style="display: none;">
        <div class="label">Gift voucher</div>
        <div class="shopp-price">$<span class="itempr">20</span>
        </div><span>Quantity: </span><span class="shopp-quantity">2</span>
        <img src="../img/erop/remove.png" class="remove">
        <br class="all">
    </div>
    <div id="each-3" class="shopp" style="display: none;">
        <div class="label">Gift voucher</div>
        <div class="shopp-price">$<span class="itempr">10</span>
        </div><span>Quantity: </span><span class="shopp-quantity">1</span>
        <img src="../img/erop/remove.png" class="remove">
        <br class="all">
    </div>
</div>

​

$('.pull-right').on('click',function(){
    alert( $('#cart-info').text()); 
    $('#cart-info').slideToggle('slow');
});

动态内容在cart-info下面。我想显示这些项目，并相应地隐藏它们。

Answer 1

将display:none;从#cart-info的子div中删除，否则他们就不会出现了！

演示：http://jsfiddle.net/tymeJV/P3WaC/1/

Answer 2

只需在滑动父元素之前显示.shopp元素：

$('.pull-right').on('click',function(){
    alert( $('#cart-info').text()); 
    $('#cart-info').find('.shopp').show();  //added line
    $('#cart-info').slideToggle('slow');

});

生活演示：http://jsfiddle.net/P3WaC/2/