并发循环中的Php错误问题

Question

我有一个SMS Api，发送短信(而不是电子邮件)给我的客户与php。现在，我正在尝试从.txt文件发送短信，所有联系人号码都在这里：

我的.txt文件

shibbir, 8801678877639
babu, 8801534552503

，所以我的while循环如下所示：

$file_handle = fopen("$file", "r");
while ( !feof( $file_handle ) ) {
    $line_of_text = fgetcsv($file_handle, 1024);
    $line_of_text[1] ."<BR>";       
    $obj = new Sender("myservername","myport","username","password","$sender", "$msg", 
"$line_of_text","2","1"); 
    $obj->Submit();     
    echo "<div class='success'>Successfully sent your message to " . $line_of_text[1] . " Thank 
    You.</div>";
}
fclose( $file_handle );

，但我得到以下错误消息：

Notice: Array to string conversion in D:\Software Installed\xampp\htdocs\evan\toplevel
\bulksms.php on line 108

Notice: Undefined offset: 1 in D:\Software Installed\xampp\htdocs\evan\toplevel\bulksms.php on 
line 106

Notice: Undefined offset: 1 in D:\Software Installed\xampp\htdocs\evan\toplevel\bulksms.php on 
line 107

我的最终目标是，用户可以通过上传.txt文件发送短信，所有联系人号码退出。因此，一旦它提交了表格，那么短信必须发送到那些联系电话号码。

1. 你们能告诉我为什么我会收到错误信息吗？
2. 这是显示2成功确认，但我希望它必须是显示1成功确认。

谢谢。

Answer 1

尝尝这个。

$file_handle = fopen("$file", "r");
$success_number = array();
    while ( !feof( $file_handle ) ) {
        $line_of_text = fgetcsv($file_handle, 1024);
        $success_number[]=$line_of_text[1]; //call this statement if msg sent successfully.
        $line_of_text  = implode(',',$line_of_text ); // i think we need to pass string to the api.
        $obj = new Sender("myservername","myport","username","password","$sender", "$msg", 
    "$line_of_text","2","1"); 
        $obj->Submit();     
    }
    echo "<div class='success'>Successfully sent your message to ".implode(',',$success_number) ."<BR> Thank You.</div>";
    fclose( $file_handle );

我的测试

my.txt

shibbir, 8801678877639
babu, 8801534552503

my.php (删除了对api的调用)

    <?php
    $file = "my.txt";
    $file_handle = fopen($file, "r");
    $success_number = array();
    while ( !feof( $file_handle ) ) {
        $line_of_text = fgetcsv($file_handle, 1024);    
        $success_number[]=$line_of_text[1]; //call this statement if msg sent successfully.
    }
    fclose( $file_handle );
    echo "<div class='success'>Successfully sent your message to " . implode(',',$success_number) ."<BR> Thank You.</div>";
?>

输出

    Successfully sent your message to 8801678877639, 8801534552503
Thank You.

Answer 2

尝试将您的代码更改为

$file_handle = fopen("$file", "r");
while (!feof($file_handle) )
{
$line_of_text = fgetcsv($file_handle, 1024);
$line_of_text[1]=$line_of_text[1] ."<BR>";       
$obj = new Sender("myservername","myport","username","password","$sender", "$msg", 
$line_of_text[1],"2","1"); 
$obj->Submit();     
echo "<div class='success'>Successfully sent your message to " . $line_of_text[1] . " Thank 
You.</div>";
}
fclose($file_handle);

Answer 3

( 1)你们能告诉我为什么会收到错误信息吗？ 2)这是显示2成功确认，但我希望它必须是显示1成功确认。

1. 它们是而不是错误。
2. 将echo DIV标记移出while循环。