Silverlight DataGrid报头RotateTransform编程实现

Question

如何在Silverlight上使用代码后面的旋转转换来旋转DataGrid中的标头文本？我没有概念，但是当我尝试使用这段代码时，是不起作用的。

    private DataGridTemplateColumn CreateColumn(int index, string header)
    {
        string cellTemp = string.Format(@"<DataTemplate xmlns=""http://schemas.microsoft.com/winfx/2006/xaml/presentation"" 
            xmlns:x=""http://schemas.microsoft.com/winfx/2006/xaml"">
             <CheckBox />
        </DataTemplate>", index);

        DataGridTemplateColumn column = new DataGridTemplateColumn();
        column.Header = header;
        column.CellTemplate = (DataTemplate)XamlReader.Load(cellTemp);

        TransformGroup traGrp = new TransformGroup(){};
        traGrp.Children.Add(new RotateTransform(){ Angle = -35});

        Style transofrm = new Style(typeof(DataGridTemplateColumn));
        transofrm.Setters.Add(new Setter(TextBlock.RenderTransformProperty, traGrp));
        column.HeaderStyle = transofrm;

        return column;
    }

知道吗？

Answer 1

好的给你，

将此资源添加到用户控件中，

<UserControl.Resources>
        <Style TargetType="sdk:DataGridColumnHeader">
            <Setter Property="Template">
                <Setter.Value>
                    <ControlTemplate TargetType="sdk:DataGridColumnHeader">
                        <Canvas x:Name="RootElement" Height="60" HorizontalAlignment="Stretch">
                            <ContentPresenter Canvas.Left="15" Canvas.Top="50" Content="{TemplateBinding Content}">
                                <ContentPresenter.RenderTransform>
                                    <RotateTransform Angle="-90"/>
                                </ContentPresenter.RenderTransform>
                            </ContentPresenter>
                        </Canvas>
                    </ControlTemplate>
                </Setter.Value>
            </Setter>
        </Style>
    </UserControl.Resources>

在codebehind.cs，你可以这样做，

private DataGridTemplateColumn CreateColumn(int index, string header)
        {
            string cellTemp = string.Format(@"<DataTemplate xmlns=""http://schemas.microsoft.com/winfx/2006/xaml/presentation"" 
            xmlns:x=""http://schemas.microsoft.com/winfx/2006/xaml"">
             <CheckBox />
             </DataTemplate>", index);
            DataGridTemplateColumn column = new DataGridTemplateColumn();
            column.Header = header;
            column.HeaderStyle = Resources["Template"] as Style;
            column.CellTemplate = (DataTemplate)XamlReader.Load(cellTemp);


            return column;
        }