递增语句和if语句

Question

我试图让if语句回显内联样式。然而，我只能获得我的条件返回在任何一个数字上的真，而不是一个数组，一个\\来分离的.

请您解释一下如何在“我的条件”中使“维京”版本和一组数字返回为真。

// Works.
$counts = 0 ;
foreach ($posts as $post) : setup_postdata($post); $counts++; 
 if ($counts == 8) {echo 'counts equals your numbers';}
endforeach; 

// This does nothing.
$numbers = array(4,8);
$counts = 0 ;
foreach ($posts as $post) : setup_postdata($post); $counts++; 
 if ($counts == $numbers) {echo 'counts equals your numbers';}
endforeach; 

// Returns true for every iteration.
$counts = 0 ;
foreach ($posts as $post) : setup_postdata($post); $counts++; 
 if ($counts == 4 || 8) {echo 'counts equals your numbers';}
endforeach; 

Answer 1

使用PHP的内置in_array函数：

if ( in_array($counts, $numbers) ) {echo 'counts equals your numbers';}

Answer 2

||的语法是：

if ($counts == 4 || $counts == 8) {echo 'counts equals your numbers';}