当我运行我的代码并进入我游戏的战斗部分时,我会得到分配给我的角色攻击、防御、伤害和健康的随机值。然而,在他们的第一轮,他们得到相同的值,他们不能重置。
例如,用户的攻击是一个从4到11的随机数。
userAtk = random.randint(4,11)我认为,每次循环运行时,它都会生成一个新值。但情况并非如此,每次我打印变量时,它的值都与第一次分配的值相同。我是不是遗漏了什么?
下面是我的代码
import random
# VARIABLES
#
#
# This variable is the user's character name
userName = input("Brave warrior, what is your name? ")
# This variable is used in the input function to pause the game
enterNext = ("Press enter to continue...")
# This variable is used to format the user input prompt
# as well as the battle text
prompt = ">>>>> "
# This variable is used to add a new line to a string
newLine = "\n"
# This variable is used to display a message when the hero dies
heroDeadmsg = userName + " has fallen!"
# These variables represent the dragon's stats (HP, ATK & DEF)
dragonHp = 100
dragonAtk = random.randint(5,10)
dragonDef = random.randrange(8)
# These variables represent the user's stats (HP, ATK & DEF)
userHp = 90
userAtk = random.randint(4,11)
userDef = random.randrange(8)
# These variables calculate battle damage and HP
dragonDmg = (userAtk - dragonDef)
dragonHp -= dragonDmg
userDmg = (dragonAtk - userDef)
userHp -= userDmg
# This variable prints the options in the battle menu
battleMenu = """Attack (a) - Magic (m) - Item (i) - Run (r)"""
# This variable determines who goes first
cointoss = random.randint(0, 1)
# These variables print the actions in each turn
dragonAttack = \
prompt + "Crimson Dragon attacks you with " + str(dragonAtk) + " ATK!"\
+ newLine + prompt + "You defend with " + str(userDef) + " DEF!"\
+ newLine + prompt
userAttack = \
prompt + "You attacked with " + str(userAtk) + " ATK!"\
+ newLine + prompt + "Crimson Dragon defends with " + str(dragonDef) + " DEF!"\
+ newLine + prompt
userMagic = \
prompt + userName + " tried to use Magic!"\
+ newLine + prompt + userName + " has no magic!"\
+ newLine + prompt
userItem = \
prompt + userName + " tried use an Item!"\
+ newLine + prompt + userName + " has no Items!"\
+ newLine + prompt
userRetreat = \
prompt + userName + " tries to retreat!"\
+ newLine + prompt + "The enemy won't let you escape!"\
+ newLine + prompt
# These variables show health during battle
printDragonhp = "Crismon Dragon has " + str(dragonHp) + " HP remaining!"
printUserhp = userName + " has " + str(userHp) + " HP remaining!"
# This variable simulates the results of a coin toss
coinToss = random.randint(0, 1)
#
#
# CONDTITIONS
#
#
# These conditions determines who attacks first
if coinToss == 0:
currentTurn = "dragon"
elif coinToss == 1:
currentTurn = "user"
else:
print("The Coin Toss Failed!")
#
#
# BATTLE MECHANICS
#
#
while currentTurn:
# Mechanics for the Crimson Dragon's Turn
if currentTurn == "dragon":
# Prints the Crimson Dragon's Attack and ends the turn
print(newLine + prompt + "Crimson Dragon moves!"\
+ newLine + prompt + newLine + dragonAttack\
+ newLine + prompt + userName + " takes " + str(userDmg) + " DMG!"\
+ newLine + prompt + printUserhp)
currentTurn = "user"
input(prompt)
# Need to implent a way to reset ATK and DEF
# Mechanics for the User's Turn
if currentTurn == "user":
# Prints the Battle Menu and asks for the User's choice
print(newLine + prompt + battleMenu\
+ newLine + prompt)
userChoice = input(prompt)
# Prints the User's Attack and ends the turn
if userChoice == "a":
print(userAttack)
if userHp < 1:
print(heroDeadmsg)
break
input (prompt)
currentTurn = "dragon"
# Prints the User's Magic and ends the turn
elif userChoice == "m":
print(userMagic)
input (prompt)
currentTurn = "dragon"
# Prints the User's Item and ends the turn
elif userChoice == "i":
print(userItem)
input (prompt)
currentTurn = "dragon"
# Prints the User's Retreat and ends the turn
elif userChoice == "r":
print(userRetreat)
input (prompt)
currentTurn = "dragon"
# Prints an error message for invalid entries
else:
print(newLine + prompt + "That is not a valid menu item."\
+ newLine + prompt + "Please try again.")发布于 2013-08-20 01:59:16
random.randint(4,11)只是在范围[4, 11]中选择一个整数并返回这个数字。因此,当您执行userAtk = random.randint(4,11)时,您只需获取一个数字并将其存储为userAtk,每次访问userAtk时,您都会得到相同的号码。
如果您希望userAtk是一种神奇的东西,每次您访问它时,在范围[4, 11]中都会表现出一个不同的数字。嗯,这并不是不可能的(见这里,快速而肮脏地尝试一下)…但这几乎肯定会导致更多的混乱,而不是利益。
例如,您有试图打印出str(userAtk)…的代码。但是,如果每次访问它时,值是不同的,则打印出来的内容将与用于计算损失的内容不同!想象一下,如果你正在玩桌面D&D,而地牢的主人滚动一个模具告诉你你的滚动,然后立即忘记了结果,并再次滚动,以确定你是否击中。所以他可能会说,“你滚了一个20,你错过了。”这不太好。
可能有用的是使userAtk实际上是一个函数:
def userAtk():
return random.randint(4, 11)对于所有相似的变量也是如此。然后,只要访问一个数字,就可以调用该函数:
def dragonDmg():
return userAtk() - dragonDef()然后,在某个地方,您需要将调用这些函数的结果存储在每个循环中的一些局部变量中。
但关键是,不管你怎么做,你必须有变量,你每次都要通过循环重新计算。
发布于 2013-08-19 23:47:30
因为据我所见,userAtk不在循环中。如果希望在循环中重置它,请在循环中调用random.randint(4,11)。
发布于 2013-08-20 00:31:52
我相信,即使你给布兰特打了一百万次电话,你还是会得到重复的(我相信你知道这一点)。我过去经常使用字典来跟踪使用过的/未使用的随机数,并检查字典是否已经使用过。可能误解了这个问题。
https://stackoverflow.com/questions/18324771
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