NPP BoxFilters与二进制数据

Question

我试图为BoxFiltering创建NPP示例，但是在8位灰度图像中，我有RGBA二进制数据。我的代码看起来是：

#include "./common/ImagesCPU.h"
#include "./common/ImagesNPP.h"
#include "./common/ImageIO.h"
#include "./common/Exceptions.h"

#include <npp.h>

void boxfilter_transform( Npp8u *oHostSrc, int width, int height ){
    size_t size = width * height * 4;

    // declare a device image and copy construct from the host image,
    // i.e. upload host to device
    npp::ImageNPP_8u_C4 oDeviceSrc(oHostSrc);

    // create struct with box-filter mask size
    NppiSize oMaskSize = {5, 5};
    // create struct with ROI size given the current mask
    NppiSize oSizeROI = {oDeviceSrc.width() - oMaskSize.width + 1, oDeviceSrc.height() - oMaskSize.height + 1};
    // allocate device image of appropriatedly reduced size
    npp::ImageNPP_8u_C4 oDeviceDst(oSizeROI.width, oSizeROI.height);
    // set anchor point inside the mask to (0, 0)
    NppiPoint oAnchor = {0, 0};
    // run box filter
    NppStatus eStatusNPP;
    eStatusNPP = nppiFilterBox_8u_C4R(oDeviceSrc.data(), oDeviceSrc.pitch(),
                                      oDeviceDst.data(), oDeviceDst.pitch(),
                                      oSizeROI, oMaskSize, oAnchor);
    NPP_ASSERT(NPP_NO_ERROR == eStatusNPP);
    // declare a host image for the result
    npp::ImageCPU_8u_C4 oHostDst(oDeviceDst.size());
    // and copy the device result data into it
    oDeviceDst.copyTo(oHostDst.data(), oHostDst.pitch());

    return 0;
}

我试着编译它并得到：

npp_filters.cpp: In function ‘void boxfilter_transform(Npp8u*, int, int)’:
npp_filters.cpp:18:44: error: no matching function for call to ‘npp::ImageNPP<unsigned char, 4u>::ImageNPP(Npp8u*&)’
npp_filters.cpp:18:44: note: candidates are:
./common/ImagesNPP.h:52:13: note: template<class X> npp::ImageNPP::ImageNPP(const npp::ImageCPU<D, N, X>&, bool)
./common/ImagesNPP.h:45:13: note: npp::ImageNPP<D, N>::ImageNPP(const npp::ImageNPP<D, N>&) [with D = unsigned char, unsigned int N = 4u]
./common/ImagesNPP.h:45:13: note:   no known conversion for argument 1 from ‘Npp8u* {aka unsigned char*}’ to ‘const npp::ImageNPP<unsigned char, 4u>&’
./common/ImagesNPP.h:40:13: note: npp::ImageNPP<D, N>::ImageNPP(const npp::Image::Size&) [with D = unsigned char, unsigned int N = 4u]
./common/ImagesNPP.h:40:13: note:   no known conversion for argument 1 from ‘Npp8u* {aka unsigned char*}’ to ‘const npp::Image::Size&’
./common/ImagesNPP.h:35:13: note: npp::ImageNPP<D, N>::ImageNPP(unsigned int, unsigned int, bool) [with D = unsigned char, unsigned int N = 4u]
./common/ImagesNPP.h:35:13: note:   candidate expects 3 arguments, 1 provided
./common/ImagesNPP.h:30:13: note: npp::ImageNPP<D, N>::ImageNPP() [with D = unsigned char, unsigned int N = 4u]
./common/ImagesNPP.h:30:13: note:   candidate expects 0 arguments, 1 provided
npp_filters.cpp:39:12: error: return-statement with a value, in function returning 'void' [-fpermissive]

怎么啦？你能告诉我正确的路吗？

现在，我的代码如下：

// declare a host image object for an 8-bit RGBA image
npp::ImageCPU_8u_C4 oHostSrc(width, height);

// copy data to oHostSrc.data()
Npp8u *nDstData = oHostSrc.data();
memcpy(nDstData, data, size * sizeof(Npp8u));

// declare a device image and copy construct from the host image,
// i.e. upload host to device
npp::ImageNPP_8u_C4 oDeviceSrc(oHostSrc);

但是现在我不能声明一个设备映像并复制(最后一行)，得到这样的错误：未定义符号: nppiMalloc_8u_C4。它能是什么？

Answer 1

在npp::ImageNPP_8u_C4中没有针对单个主机指针的构造函数，您需要首先在npp::ImageCPU_8u_C4中包装主机数组，就像在您所包含的ImageIO.h中所做的那样。关键是，您的NPP映像需要获取一些维度信息，这些信息是oDeviceSrc当前缺少的。