加油：：精神:气用stl容器

Question

我试着用parse解析一些东西，精灵的气库，我遇到了一个问题。根据精神医生，a >> b应该生成tuple<A, B>类型的东西。但是这是一个boost::tuple (也就是融合向量)，而不是std::tuple (我想要)。

有什么简单的方法可以在boost::tuple std::tuple**?** => std::tuple**？**之间进行这种转换吗？

同一文档页指出，*a应该生成类型为vector<A>的东西。这似乎产生了一个std::vector<A> (或者某种可以隐式转换为std::vector<A>的boost::vector<A> )。我只想知道这种行为是否适用于元组。

Answer 1

简短答覆：

使用#include <boost/fusion/adapted/std_tuple.hpp>。

更完整的答案：

如您所见，这里

在属性表中，我们将只使用vector<A>和tuple<A, B...>作为占位符。vector<A>的表示法代表任何包含A类型的STL容器元素，tuple<A, B...>表示任何Boost.Fusion序列保持A、B、.等要素。最后，未使用的表示unused_type。

因此，当解析器/生成器有一个属性为tuple<A,B...>时，您可以使用任何融合序列(例如融合：：向量或融合：：list)或任何可以适应融合序列的内容(例如boost：：数组、boost::tuple、std：：结对、std：：tuple、std::tuple，您自己使用BOOST_FUSION_ADAPT_STRUCT的结构)。

当它有vector<A>时，如果您的元素是对的，可以使用std：：vector<A>、std::list，甚至std::map。如果您还专门化了几个定制点，也可以使用自己的结构(至少在boost：：container_value和push_back_container中是这样的)。

std：：对

为了能够将std::pair与spirit一起使用，只需添加一个标题：

#include <boost/fusion/include/std_pair.hpp>
...
qi::rule<Iterator,std::pair<int,double>()> rule = 
    qi::int_ >> qi::lit(',') >> qi::double_;

std::tuple

从boost 1.48.0开始，您可以对std：：tuple执行相同的操作：

#include <boost/fusion/adapted/std_tuple.hpp> 
...
qi::rule<Iterator,std::tuple<int,std::string,double>()> rule =
    qi::int_ >> qi::lit(',') >> +~qi::char_(',') >> qi::lit(',') >> qi::double_;

您自己的结构

在BOOST_FUSION_ADAPT_STRUCT的帮助下，您可以很容易地调整您的自定义结构：

#include <boost/fusion/include/adapt_struct.hpp>
...
struct normal_struct
{
    int integer;
    double real;
};

BOOST_FUSION_ADAPT_STRUCT(
    normal_struct,
    (int, integer)
    (double, real)
)
...
qi::rule<Iterator,normal_struct()> rule =
    qi::int_ >> qi::lit(',') >> qi::double_;

但是，有一个已知的限制，当您尝试使用具有单个元素(也是容器编译)的结构时，除非将qi::eps >> ...添加到您的规则中，否则会失败。

struct struct_with_single_element_container
{
    std::vector<int> cont;
};

BOOST_FUSION_ADAPT_STRUCT(
    struct_with_single_element_container,
    (std::vector<int>, cont)
)
...
qi::rule<Iterator,struct_with_single_element_container()> rule =
    qi::eps >> qi::int_%qi::lit(',');

std::map

您可以简单地使用std::map作为std：：对的容器。不过，请记住，如果输入中有重复的键，则只有第一个键将被插入到映射中(当然，如果使用multimap，所有内容都将被插入)：

#include <boost/fusion/include/std_pair.hpp>
...
qi::rule<std::string::const_iterator, std::pair<double,int>()> pair_rule = 
    qi::double_ >> qi::lit('=') >> qi::int_;
qi::rule<std::string::const_iterator, std::map<double,int>()> rule = 
    pair_rule%qi::lit(',');
//You can also use
//qi::rule<std::string::const_iterator, std::map<double,int>()> rule =
    //(qi::double_ >> qi::lit('=') >> qi::int_)%qi::lit(',');

将您自己的结构为容器

使用灵性的定制点，您还可以使您的结构在处理属性时表现得像容器一样。您需要专门处理的最低限度是is_container、container_value和push_back_container。以下是几个例子：

第一个很简单(而且很傻)。它使您的结构具有一个与std::vector<int>兼容的属性。每次解析int时，它都被添加到累加器中的总数中。您可以找到不那么愚蠢的方法这里和这里 (在“旧答案”中)。

struct accumulator
{
    accumulator(): total(){}
    int total;
};

namespace boost{ namespace spirit{ namespace traits
{
    template<>
    struct is_container<accumulator> : boost::mpl::true_
    {};

    template<>
    struct container_value<accumulator>
    {
        typedef int type;
    };

    template<>
    struct push_back_container<accumulator,int>
    {
        static bool call(accumulator& c, int val)
        {
            c.total+=val;
            return true;
        }
    };
}}}
...
qi::rule<Iterator,accumulator()> rule =
    qi::int_%qi::lit(',');

第二个问题稍微复杂一些(不多)。它使您的结构具有一个与std::vector<boost::variant<int,std::string> >兼容的属性。当一个int被解析时，它将被添加到分发服务器中的ints容器中，类似地，字符串也存储在strings容器中。使用此示例(1、2和3.)。

struct distributor
{
    distributor():ints(),strings(){}
    std::vector<int> ints;
    std::vector<std::string> strings;
};

namespace boost{ namespace spirit{ namespace traits
{
    template<>
    struct is_container<distributor> : boost::mpl::true_
    {};

    template<>
    struct container_value<distributor>
    {
        typedef boost::variant<int,std::string> type;
    };

    template<>
    struct push_back_container<distributor,int>
    {
        static bool call(distributor& c, int val)
        {
            c.ints.push_back(val);
            return true;
        }
    };

    template<>
    struct push_back_container<distributor,std::string>
    {
        static bool call(distributor& c, std::string const& val)
        {
            c.strings.push_back(val);
            return true;
        }
    };
}}}
...
qi::rule<std::string::const_iterator, std::string()> string_rule = 
    +~qi::char_(',');
qi::rule<std::string::const_iterator, distributor()> rule = 
    (qi::int_ | string_rule)%qi::lit(',');

一个cpp文件中的所有测试

#include <iostream>
#include <string>
#include <utility>
#include <tuple>
#include <list>
#include <vector>
#include <map>

#include <boost/fusion/include/std_pair.hpp>
#include <boost/fusion/include/adapt_struct.hpp>
#include <boost/fusion/adapted/std_tuple.hpp> 

#include <boost/spirit/include/qi.hpp>

#include <boost/variant.hpp>

namespace qi=boost::spirit::qi;

struct normal_struct
{
    int integer;
    double real;
};

struct struct_with_single_element_container
{
    std::vector<int> cont;
};

BOOST_FUSION_ADAPT_STRUCT(
    normal_struct,
    (int, integer)
    (double, real)
)

BOOST_FUSION_ADAPT_STRUCT(
    struct_with_single_element_container,
    (std::vector<int>, cont)
)

struct accumulator
{
    accumulator(): total(){}
    int total;
};

namespace boost{ namespace spirit{ namespace traits
{
    template<>
    struct is_container<accumulator> : boost::mpl::true_
    {};

    template<>
    struct container_value<accumulator>
    {
        typedef int type;
    };

    template<>
    struct push_back_container<accumulator,int>
    {
        static bool call(accumulator& c, int val)
        {
            c.total+=val;
            return true;
        }
    };
}}}

struct distributor
{
    distributor():ints(),strings(){}
    std::vector<int> ints;
    std::vector<std::string> strings;
};

namespace boost{ namespace spirit{ namespace traits
{
    template<>
    struct is_container<distributor> : boost::mpl::true_
    {};

    template<>
    struct container_value<distributor>
    {
        typedef boost::variant<int,std::string> type;
    };

    template<>
    struct push_back_container<distributor,int>
    {
        static bool call(distributor& c, int val)
        {
            c.ints.push_back(val);
            return true;
        }
    };

    template<>
    struct push_back_container<distributor,std::string>
    {
        static bool call(distributor& c, std::string const& val)
        {
            c.strings.push_back(val);
            return true;
        }
    };
}}}


int main()
{
    {
        std::pair<int,double> parsed;
        qi::rule<std::string::const_iterator, std::pair<int,double>()> rule = 
                    qi::int_ >> qi::lit(',') >> qi::double_;
        std::string test="1,2.5";
        std::string::const_iterator iter=test.begin(), end=test.end();
        bool result = qi::parse(iter,end,rule,parsed);
        if(result && iter==end)
        {
            std::cout << "Success." << std::endl;
            std::cout << "First: " << parsed.first << ", Second: " << parsed.second << std::endl;
        }
        else
        {
            std::cout << "Failure." << std::endl;
            std::cout << "Unparsed: " << std::string(iter,end) << std::endl;
        }
    }

    {
        std::tuple<int,std::string,double> parsed;
        qi::rule<std::string::const_iterator, std::tuple<int,std::string,double>()> rule = 
                    qi::int_ >> qi::lit(',') >> +~qi::char_(',') >> qi::lit(',') >> qi::double_;
        std::string test="1,abc,2.5";
        std::string::const_iterator iter=test.begin(), end=test.end();
        bool result = qi::parse(iter,end,rule,parsed);
        if(result && iter==end)
        {
            std::cout << "Success." << std::endl;
            std::cout << "get<0>: " << std::get<0>(parsed) << ", get<1>: " << std::get<1>(parsed) << ", get<2>: " << std::get<2>(parsed) << std::endl;
        }
        else
        {
            std::cout << "Failure." << std::endl;
            std::cout << "Unparsed: " << std::string(iter,end) << std::endl;
        }
    }

    {
        normal_struct parsed;
        qi::rule<std::string::const_iterator, normal_struct()> rule = 
                    qi::int_ >> qi::lit(',') >> qi::double_;
        std::string test="1,2.5";
        std::string::const_iterator iter=test.begin(), end=test.end();
        bool result = qi::parse(iter,end,rule,parsed);
        if(result && iter==end)
        {
            std::cout << "Success." << std::endl;
            std::cout << "integer: " << parsed.integer << ", real: " << parsed.real << std::endl;
        }
        else
        {
            std::cout << "Failure." << std::endl;
            std::cout << "Unparsed: " << std::string(iter,end) << std::endl;
        }
    }

    {
        struct_with_single_element_container parsed;
        //there is a problem when you have a struct with a single element container, the workaround is simply adding qi::eps to the rule
        qi::rule<std::string::const_iterator, struct_with_single_element_container()> rule = 
                    qi::eps >> qi::int_%qi::lit(','); 
        std::string test="1,2";
        std::string::const_iterator iter=test.begin(), end=test.end();
        bool result = qi::parse(iter,end,rule,parsed);
        if(result && iter==end)
        {
            std::cout << "Success." << std::endl;
            std::cout << "[0]: " << parsed.cont[0] << ", [1]: " << parsed.cont[1] << std::endl;
        }
        else
        {
            std::cout << "Failure." << std::endl;
            std::cout << "Unparsed: " << std::string(iter,end) << std::endl;
        }
    }

    {
        std::list<int> parsed;
        qi::rule<std::string::const_iterator, std::list<int>()> rule = 
                    qi::int_%qi::lit(',');
        std::string test="1,2";
        std::string::const_iterator iter=test.begin(), end=test.end();
        bool result = qi::parse(iter,end,rule,parsed);
        if(result && iter==end)
        {
            std::cout << "Success." << std::endl;
            std::cout << "front: " << parsed.front() << ", back: " << parsed.back() << std::endl;
        }
        else
        {
            std::cout << "Failure." << std::endl;
            std::cout << "Unparsed: " << std::string(iter,end) << std::endl;
        }
    }

    {
        std::map<double,int> parsed;
        qi::rule<std::string::const_iterator, std::pair<double,int>()> pair_rule = 
                    qi::double_ >> qi::lit('=') >> qi::int_;
        qi::rule<std::string::const_iterator, std::map<double,int>()> rule = 
                    pair_rule%qi::lit(',');
        std::string test="2.5=1,3.5=2";
        std::string::const_iterator iter=test.begin(), end=test.end();
        bool result = qi::parse(iter,end,rule,parsed);
        if(result && iter==end)
        {
            std::cout << "Success." << std::endl;
            std::cout << "map[2.5]: " << parsed[2.5] << ", map[3.5]: " << parsed[3.5] << std::endl;
        }
        else
        {
            std::cout << "Failure." << std::endl;
            std::cout << "Unparsed: " << std::string(iter,end) << std::endl;
        }
    }

    {
        accumulator parsed;
        qi::rule<std::string::const_iterator, accumulator()> rule = 
                    qi::int_%qi::lit(',');
        std::string test="1,2,3";
        std::string::const_iterator iter=test.begin(), end=test.end();
        bool result = qi::parse(iter,end,rule,parsed);
        if(result && iter==end)
        {
            std::cout << "Success." << std::endl;
            std::cout << "total: " << parsed.total << std::endl;
        }
        else
        {
            std::cout << "Failure." << std::endl;
            std::cout << "Unparsed: " << std::string(iter,end) << std::endl;
        }
    }

    {
        distributor parsed;
        qi::rule<std::string::const_iterator, std::string()> string_rule = 
                    +~qi::char_(',');
        qi::rule<std::string::const_iterator, distributor()> rule = 
                    (qi::int_ | string_rule)%qi::lit(',');
        std::string test="abc,1,2,def,ghi,3,jkl";
        std::string::const_iterator iter=test.begin(), end=test.end();
        bool result = qi::parse(iter,end,rule,parsed);
        if(result && iter==end)
        {
            std::cout << "Success." << std::endl;
            std::cout << "ints" << std::endl;
            for(auto val: parsed.ints)
                std::cout << val << std::endl;
            std::cout << "strings" << std::endl;
            for(const auto& val: parsed.strings)
                std::cout << val << std::endl;
        }
        else
        {
            std::cout << "Failure." << std::endl;
            std::cout << "Unparsed: " << std::string(iter,end) << std::endl;
        }
    }

}