使用JSON或json-lib将XML转换为json的问题

Question

在某些节点中包含一些html内容的xml如下

<detail>
&lt;P&gt;Students should avoid purchasing their textbooks at the first store that they browse. Instead, they should investigate the alternatives offered by other online booksellers. Price isn't the only factor to consider when making an online purchase. Students should also factor in shipping costs and delivery time when making their buying decision.&lt;/P&gt;
</detail>

同时，通过Json或json-lib将xml转换为json，

import net.sf.json.JSON;
import net.sf.json.xml.XMLSerializer; 
.....
JSONObject jsonObject = XML.toJSONObject(xml.toString());
......

xml是包含xml内容的字符串。

我应该得到json字符串

{"detail":"<P>Students should avoid purchasing their textbooks at the first store that they browse. Instead, they should investigate the alternatives offered by other online booksellers. Price isn't the only factor to consider when making an online purchase. Students should also factor in shipping costs and delivery time when making their buying decision.</P>"}

但是输出就像

{"detail":{"P":"Students should avoid purchasing their textbooks at the first store that they browse. Instead, they should investigate the alternatives offered by other online booksellers. Price isn't the only factor to consider when making an online purchase. Students should also factor in shipping costs and delivery time when making their buying decision."}}

这是不恰当的。

有人能告诉我如何解决这个问题吗？

Answer 1

尝试使用来自www.json.org的库而不是net.sf.json.JSON

import org.json.JSONObject;
import org.json.XML;

String xmlString = "<detail>&lt;P&gt;Students should avoid purchasing their textbooks at the first store that they browse. Instead, they should investigate the alternatives offered by other online booksellers. Price isn't the only factor to consider when making an online purchase. Students should also factor in shipping costs and delivery time when making their buying decision.&lt;/P&gt;</detail>";
System.out.println("Initial XML : " + xmlString);
JSONObject jsonObj = (XML.toJSONObject(xmlString));
System.out.println("Converted JSON : " + jsonObj.toString());
System.out.println("Back to converted XML : " + XML.toString(jsonObj));

在我看来，你会得到更好的结果：

Initial XML : <detail>&lt;P&gt;Students should avoid purchasing their textbooks at the first store that they browse. Instead, they should investigate the alternatives offered by other online booksellers. Price isn't the only factor to consider when making an online purchase. Students should also factor in shipping costs and delivery time when making their buying decision.&lt;/P&gt;</detail>
Converted JSON : {"detail":"<P>Students should avoid purchasing their textbooks at the first store that they browse. Instead, they should investigate the alternatives offered by other online booksellers. Price isn't the only factor to consider when making an online purchase. Students should also factor in shipping costs and delivery time when making their buying decision.<\/P>"}
Back to converted XML : <detail>&lt;P&gt;Students should avoid purchasing their textbooks at the first store that they browse. Instead, they should investigate the alternatives offered by other online booksellers. Price isn&apos;t the only factor to consider when making an online purchase. Students should also factor in shipping costs and delivery time when making their buying decision.&lt;/P&gt;</detail>