Django为“with参数”(7，)和关键字参数“{}”未找到而形成反向形式

Question

在过去的一天里，我遇到了这个错误，似乎无法解决。

Reverse for '' with arguments '(7,)' and keyword arguments '{}' not found.

我的目标是让用户从我的drui_index页面中选择疾病。然后，用户被带到drui页面添加或编辑指示器。在我的模型中，每种疾病都有多种指标。当我到达drui页面时，我会得到上面的错误，并且不知道原因。错误中的'7‘是疾病表中的PK。

Views.py

def drui_index(request):
   disease_list = Disease.objects.all()
   context = {'disease_list':disease_list}
   return render(request, 'drui_index.html', context)


def drui(request, disease_id):
   disease = get_object_or_404(Disease, pk=disease_id)  

   if request.method == "POST":

      diseaseForm = DiseaseForm(request.POST, instance=disease)
      indicatorInlineFormSet = IndicatorFormSet(request.POST, request.FILES, instance=disease)

      if diseaseForm.is_valid():
         new_disease = diseaseForm.save(commit=False)
         indicatorInlineFormSet.save()
         return HttpResponseRedirect(reverse('drui', kwargs={'disease_id':disease_id}))

   else:
      diseaseForm = DiseaseForm(instance=disease)
      indicatorInlineFormSet = IndicatorFormSet(instance=disease)

   return render(request, 'drui.html', {'disease':disease, 'diseaseForm':diseaseForm, 'indicatorInlineFormSet': indicatorInlineFormSet}) 

drui.html

 <form class="disease_form" action="{% url drui disease.id %}" method="post">{% csrf_token %}
  {{ disease }}
  {{ diseaseForm.as_table }}
  {{ indicatorInlineFormSet.as_table }}

urls.py

url(r'^drui_index/$', 'Physician_UI.views.drui_index', name='drui_index'),
url(r'^drui_index/(?P<disease_id>\d+)/$', 'Physician_UI.views.drui', name='drui'),

forms.py

class DiseaseForm(forms.ModelForm):
    disease = forms.ModelChoiceField(queryset=Disease.objects.all())

    class Meta:
       model = Disease

IndicatorFormSet = inlineformset_factory(Disease, 
    Indicator,
    can_delete=False,
    extra=MAX_INDICATORS)

在我的views.py中，我不认为我需要调用diseaseForm，因为我已经在drui_index中选择了一种疾病。不过，我不认为这会造成问题。

Answer 1

我想你漏掉了url名字的引号：

{% url drui disease.id %}

应该是(如果您正在使用django >= 1.5)或在模板中使用{% load url from future %}：

{% url "drui" disease.id %}

Answer 2

您的url标记应该是{% url "drui" disease_id=disease.id %}，因为您需要传递关键字参数。

有关更多信息，请参见文档。

由于您从未保存新条目，所以我认为您只是使用表单来显示ModelChoiceField，在这种情况下，您不需要ModelForm

class DiseaseForm(forms.Form):
    disease = forms.ModelChoiceField(queryset=Disease.objects.all())

这样，就可以避免commit=False部分。

您应该总是为您的else设置一个if form.is_valid()

from django.shortcuts import redirect

def drui(request, disease_id):
   disease = get_object_or_404(Disease, pk=disease_id)
   ctx = {}
   ctx['disease'] = disease  
   ctx['indicatorInlineFormSet'] = IndicatorFormSet()
   ctx['diseaseForm'] = DiseaseForm()

   if request.method == "POST":

      diseaseForm = DiseaseForm(request.POST)
      indicatorInlineFormSet = IndicatorFormSet(request.POST, request.FILES)

      if diseaseForm.is_valid():
         return redirect('drui', disease_id=disease_id)
      else:
         # Form wasn't valid, return the same view to display the errors
         ctx['diseaseForm'] = diseaseForm
         ctx['indicatorInlineFormset'] = indicatorInlineFormset 
         return render(request, 'drui.html', ctx)

   else:

       return render(request, 'drui.html', ctx)