嗨,我想用运算符IN搜索,但总是返回一个空的列表,有什么问题吗?我的单元测试。我想要的是通过描述或相似的词来搜索产品。(未来我假装是模糊的)。
private GraphDatabaseService graph;
private Index<Node> indexProduct;
private ExecutionEngine engine;
@Before
public void prepareTestDatabase() {
TestGraphDatabaseFactory testGraphDatabaseFactory = new TestGraphDatabaseFactory();
this.graph = testGraphDatabaseFactory.newEmbeddedDatabase("/tmp/neo4j/tests");
this.indexProduct = this.graph.index().forNodes("node_product");
this.engine = new ExecutionEngine(this.graph, StringLogger.SYSTEM);
this.loadDataForTest();
}
private void loadDataForTest() {
Transaction tx = this.graph.beginTx();
List<String> similarities = new ArrayList<>();
similarities.add("televisor");
similarities.add("tv");
String description = "televisão";
Product product = new Product(description, similarities);
Node node = this.graph.createNode(DynamicLabel.label(product.description));
node.setProperty("description", product.description);
node.setProperty("similarities", product.similarities);
this.indexProduct.add(node, "PRODUCT", product.description);
tx.success();
tx.finish();
}
@Test
public void searchByDescription(){
String description = "televisão";
List<String> list = new ArrayList<>();
ExecutionResult result = this.engine.execute("start n=node:node_product('PRODUCT:*') WHERE HAS(n.similarities) AND n.similarities IN ['tv'] return n.description");
for (Map<String, Object> row : result) {
for (Entry<String, Object> column : row.entrySet()) {
Object value = column.getValue();
list.add(String.valueOf(value));
}
}
Assert.assertTrue(list.contains(description));
}这是Product
class Product {
String description;
String[] similarities;
Product(String description, List<String> similaritiesList) {
super();
this.description = description;
this.similarities = new String[similaritiesList.size()];
for (int i=0; i<similaritiesList.size(); i++)
this.similarities[i] = similaritiesList.get(i);
}发布于 2013-08-01 08:34:55
我希望我把你的用词做对了。但我觉得你的赛弗查询有点混乱。您的查询:
"start n=node:node_product('PRODUCT:*') WHERE HAS(n.similarities) AND n.similarities IN ['tv'] return n.description"让我们来看看n.similarities IN ['tv']。属性similarities是一个数组。['tv']是一个字符串数组。因此,表达式`n.similarities IN ['tv']总是计算为false,因为['tv']不包含任何数组,更不用说similarities数组了。
最后我想你还有别的意思,就是。
'tv' IN n.similarities这是对的吗?您希望检查字符串tv是否包含在similarities数组中。当我以这种方式更改查询时,即产生的查询将是
start n=node:node_product('PRODUCT:*') WHERE HAS(n.similarities) AND 'tv' IN n.similarities return n.description然后,改编后的测试课程对我有用。
https://stackoverflow.com/questions/17981501
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