无法获得使用$.ajax({data})发送到PHP的变量

Question

我已经尝试过这些JS代码组合：

var aion_settings = [];

function aion_save_settings(){

    //Users on the Site Frontend
    $('.setting-site-users').each(function(){
        aion_settings[$(this).prop('id')]=$(this).is(':checked');
    });

    console.log(aion_settings);

    $.ajax({
        method:'post',
        url:'/save_settings',
        dataType:'json',
        data:{
            settings: function(){
                return aion_settings;
            },
            other_data: 'Other Data'
        },
        success:function(result){
            console.log(result);
        }
    });
}

还有..。

function aion_save_settings(){

    var aion_settings = [];

    //Users on the Site Frontend
    $('.setting-site-users').each(function(){
        aion_settings[$(this).prop('id')]=$(this).is(':checked');
    });

    console.log(aion_settings);

    $.ajax({
        method:'post',
        url:'/save_settings',
        dataType:'json',
        data:{
            settings: aion_settings,
            other_data: 'Other Data'
        },
        success:function(result){
            console.log(result);
        }
    });
}

..and

var aion_settings = [];

function aion_save_settings(){

    //Users on the Site Frontend
    $('.setting-site-users').each(function(){
        aion_settings[$(this).prop('id')]=$(this).is(':checked');
    });

    console.log(aion_settings);

    $.ajax({
        method:'post',
        url:'/save_settings',
        dataType:'json',
        data:{
            settings: aion_settings,
            other_data: 'Other Data'
        },
        success:function(result){
            console.log(result);
        }
    });
}

..and这些组合体与：

$.ajax({
    method:'post',
    url:'/save_settings',
    dataType:'json',
    data:aion_settings,
    success:function(result){
        console.log(result);
    }
});

在这个JQuery页面上，它甚至有下面的示例：

var xmlDocument = [create xml document];
var xmlRequest = $.ajax({
  url: "page.php",
  processData: false,
  data: xmlDocument
});

xmlRequest.done(handleResponse);

在接收端，我有以下PHP代码：

$app->post('/save_settings',function() use ($app){

    $aion_settings=$app->request()->post();

    var_dump($aion_settings);

    //Save the aion_settings
    if(aion_logged_in_user_super()){

        global $aion_db;
        if(is_array($aion_settings)) foreach($aion_settings as $setting_key => $setting){

            //Get the setting's ID
            $current_setting = array();
            $current_setting = $aion_db->queryFirstRow("SELECT id FROM settings WHERE setting_key=%s",$setting_key);

            if(!isset($current_setting['id'])) $current_setting['id']=NULL;

            $aion_db->insertUpdate('settings',array(
                'id'=>$current_setting['id'],
                'setting_key'=>$setting_key,
                'value'=>serialize($setting)
            ));
        }
    }
});

aion_settings是在发送$.ajax请求之前正确设置的。但是，在PHP端没有捕获对象settings，尽管other_data被捕获了吗？下面的最后一行显示了通过console.log准备好的对象，但没有通过$.ajax设置。我很困惑，有什么帮助吗？

​

​

​

​

Answer 1

您的data函数的$.ajax参数应该具有以下格式：

data: {
    'settings': aion_settings,
    'other_data': 'Other Data'
},

Answer 2

我就是这样修好的：

JS侧：

function aion_save_settings(){

    var aion_settings = new Object();   

    //Users on the Site Frontend
    $('.setting-site-users').each(function(){
        aion_settings[$(this).prop('id')]=$(this).is(':checked');
    });

    console.log(aion_settings);

    $.ajax({
        method:'post',
        url:'/save_settings',
        dataType:'json',
        data:aion_settings,
        success:function(result){
            console.log(result);
        }
    });
}

PHP：

$app->post('/save_settings',function() use ($app){

    $aion_settings=$app->request()->post(); 

    var_dump($aion_settings);

    //Save the aion_settings
    if(aion_logged_in_user_super()){

        global $aion_db;
        if(is_array($aion_settings)) foreach($aion_settings as $setting_key => $setting){

            //Get the setting's ID
            $current_setting = array();
            $current_setting = $aion_db->queryFirstRow("SELECT id FROM settings WHERE setting_key=%s",$setting_key);

            if(!isset($current_setting['id'])) $current_setting['id']=NULL;

            $aion_db->insertUpdate('settings',array(
                'id'=>$current_setting['id'],
                'setting_key'=>$setting_key,
                'value'=>serialize($setting)
            ));
        }
    }
});

请与我上面的问题作比较。

​

​

​

​