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REST api与laravel 4和sentry 2的认证
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Stack Overflow用户
提问于 2013-07-30 00:47:57
回答 1查看 1.9K关注 0票数 0

我正在用laravel 4和sentry 2构建一个RESTful API,我尝试用postSignin方法创建API,但是failed.correction在postSignin中乞求--这是过滤器和路由。

滤波器

代码语言:javascript
复制
    Route::filter('api', function()
    {
    // Check if the user is logged in
    if ( ! Sentry::check())
    {   
        return Response::json(array('digle'=> array(
            'status' => 1,
            'desc' => 'Unauthorized',
        )));
    }
});

路由

代码语言:javascript
复制
    Route::group(array('prefix' => 'api/v1','before' => 'api'), function()
    {
    //Test
    Route::get('/', array('as'=>'/', 'uses'=>'ApiTestController@getIndex'));

    //Login
    Route::get('signin', array('uses' => 'ApiTestController@getSignin'));
    Route::post('signin', 'ApiTestController@postSignin');

    //Logout
    Route::get('logout', array('uses' => 'ApiTestController@getLogout'));

});

控制器

代码语言:javascript
复制
 /**
 * Route /signin 
 *
 * @return Response POST 
 */
public function postSignin()
{
    //Declare the rules for the form validation
    $rules = array(
        'email'    => 'required|email',
        'password' => 'required|between:3,32',
    );

    // Create a new validator instance from our validation rules
    $validator = Validator::make(Input::all(), $rules);

    // If validation fails, we'll exit the operation now.
    if ($validator->fails())
    {
        // Ooops.. something went wrong
        //return Redirect::back()->withInput()->withErrors($validator);
        return Response::json(array('digle' => array(
           'Error' => 'error',
        )));
    }

    try
    {   
        $userdata = array(
            'email' => Input::get('email'),
            'password'=> Input::get('password')
        );
        // Try to log the user in
        Sentry::authenticate($userdata, false);


        return Response::json(array('digle' => array(
            'status' => 0,
            'desc' => 'succes'
        )));
    }
    catch (Cartalyst\Sentry\Users\UserNotFoundException $e)
    {
        return Response::json(array('digle' => array(
            'status' => $this->messageBag->add('email', Lang::get('auth/message.account_not_found'))
        )));

    }
    catch (Cartalyst\Sentry\Users\UserNotActivatedException $e)
    {
        return Response::json(array('digle' => array(
            'status' => $this->messageBag->add('email', Lang::get('auth/message.account_not_activated'))
        )));

    }
    catch (Cartalyst\Sentry\Throttling\UserSuspendedException $e)
    {
        return Response::json(array('digle' => array(
            'status' => $this->messageBag->add('email', Lang::get('auth/message.account_suspended'))
        )));

    }
    catch (Cartalyst\Sentry\Throttling\UserBannedException $e)
    {
        return Response::json(array('digle' => array(
            'status' => $this->messageBag->add('email', Lang::get('auth/message.account_banned'))
        )));

    }

    //something went wrong
    return Response::json(array('digle' => array(
            'status' => 0
    )));
}

并使用params、电子邮件和密码发出get请求http://xxx.xx/api/v1/signin,然后测试代码,使用邮递员或test客户端。

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2014-05-22 07:37:14

您的在route =>‘api’筛选器中对于签名路由是活动的.

过滤器阻止'@postSignin‘操作的运行,因此您将始终看到过滤器生成的“未经授权的”响应。

解决方案:您必须将“signin”路由移出“api”组之外,或者将该操作排除在被哨兵检查筛选的范围之外。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/17936609

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