我想看到我的时间线在我的逻辑猫,或其他时间线硬编码用户名和密码。我使用twitter4j和twitter4j作为库:这是我的当前代码:
ConfigurationBuilder configurationBuilder = new ConfigurationBuilder();
configurationBuilder.setDebugEnabled(true);
configurationBuilder.setOAuthConsumerKey(CONSUMER_KEY);
configurationBuilder.setOAuthConsumerSecret(SECRET_KEY);
configurationBuilder.setOAuthAccessToken(ACCESS_TOKEN);
configurationBuilder
.setOAuthAccessTokenSecret(ACCESS_TOKEN_SECRET);
configurationBuilder.setUseSSL(true);
Configuration configuration = configurationBuilder.build();
Twitter twitter = new TwitterFactory(configuration)
.getInstance();
try {
List<Status> statuses = twitter.getHomeTimeline();
Log.d(TAG, "Showing home timeline.");
for (Status status : statuses) {
Log.d(TAG,
status.getUser().getName() + ":"
+ status.getText());
}
} catch (TwitterException e) {
Log.d(TAG, "TwitterException: " + e.toString());
}CONSUMER_KEY:是我在dev.twitter.com上注册应用程序时为SECRET_KEY、ACCESS_TOKEN和ACCESS_TOKEN_SECRET注册的用户密钥。
,这是我的logcat输出:
07-24 06:29:16.027: D/FeedsActivity(1621): TwitterException: No authentication challenges found
07-24 06:29:16.027: D/FeedsActivity(1621): Relevant discussions can be found on the Internet at:
07-24 06:29:16.027: D/FeedsActivity(1621): http://www.google.co.jp/search?q=e5488403 or
07-24 06:29:16.027: D/FeedsActivity(1621): http://www.google.co.jp/search?q=0a0b625e
07-24 06:29:16.027: D/FeedsActivity(1621): TwitterException{exceptionCode=[e5488403-0a0b625e 6ece33f2-3760e528], statusCode=-1, message=null, code=-1, retryAfter=-1, rateLimitStatus=null, version=3.0.3}发布于 2013-07-25 06:09:10
因为代码是清晰的:)我认为问题在于twitter设置。就是这样。我重新创建了另一个应用程序,并确保启用以下功能:
Allow this application to be used to Sign in with Twitter糟糕的异常处理和异常是这里的主要问题(TwitterException)。没有很好的记录。
https://stackoverflow.com/questions/17826877
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