PHP -删除时间内的最后一个字符

Question

我知道很多函数可以删除php中的char。但我很困惑地删除了这个:我要删除"，“从

<?php
include '../config/settings.php';
$query = "SELECT keyword,count(*) AS jumlah 
FROM search GROUP BY keyword ASC";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{
$data= "['$row[keyword]', $row[jumlah]],<br>";
echo $data;}
?> 

将产生以下结果：

['Smartfren', 1],
['Telkomsel', 1],

我想要的输出如下：

['Smartfren', 1],
['Telkomsel', 1]

怎么做？

非常感谢你的回应。

更新

基于@orangpill回答说，我打印了如下数据：

['ABC',   6597],
['XYZ',   4479],
['PQR',   2075],
['Others', 450]

我想做一个图表，比如说js图表的代码必须是这样的：

data: [
                ['Firefox',   45.0],
                ['IE',       26.8],
                {
                    name: 'Chrome',
                    y: 12.8,
                    sliced: true,
                    selected: true
                },
                ['Safari',    8.5],
                ['Opera',     6.2],
                ['Others',   0.7]
            ]

基于@orangepill现在我的代码：

  <?php
    include '../config/settings.php';
    $query = "SELECT keyword,count(*) AS jumlah 
    FROM search GROUP BY keyword ASC";
    $result = mysql_query($query);
    $data = array();
    while($row = mysql_fetch_array($result))
{
    $data[] = "['$row[keyword]', $row[jumlah]]";
}

echo implode(",<br/>", $data);
    ?>
    <script type="text/javascript">
      $(function () {
            $('#container').highcharts({
                chart: {
                    plotBackgroundColor: null,
                    plotBorderWidth: null,
                    plotShadow: false
                },
                title: {
                    text: 'Presentase Sentimen Positif'
                },
                tooltip: {
                    pointFormat: '{series.name}: <b>{point.percentage}%</b>',
                    percentageDecimals: 1
                },
                plotOptions: {
                    pie: {
                        allowPointSelect: true,
                        cursor: 'pointer',
                        dataLabels: {
                            enabled: true,
                            color: '#000000',
                            connectorColor: '#000000',
                            formatter: function() {
                                return '<b>'+ this.point.name +'</b>: '+ Math.round(this.percentage) +' %';
                            }
                        }
                    }
                },
                series: [{
                    type: 'pie',
                    name: 'Nilai',
                    data: [


    <?php     while($row = mysql_fetch_array($result))
    {
        $data[] = "['$row[keyword]', $row[jumlah]]";
    }

    echo implode(",<br/>", $data); ?>
                    ]
                }]
            });
        });
    </script>

Answer 1

通过构建数组并在您想要输出时将其内爆，这样做对您来说可能是有意义的。

<?php
include '../config/settings.php';
$query = "SELECT keyword,count(*) AS jumlah 
FROM search GROUP BY keyword ASC";
$result = mysql_query($query);
$data = array();
while($row = mysql_fetch_array($result))
{
    $data[] = "['$row[keyword]', $row[jumlah]]";
}

echo implode(",<br/>", $data);
?>

如果要用javascript格式化这些数据以供使用，更好的方法应该是使用json_encode。

<?php
include '../config/settings.php';
$query = "SELECT keyword,count(*) AS jumlah 
FROM search GROUP BY keyword ASC";
$result = mysql_query($query);
$data = array();
while($row = mysql_fetch_array($result))
{
    $data[] = array($row[keyword], (int)$row[jumlah]);
}

echo "var data =  ".json_encode($data).";";
?> 

Answer 2

您还可以使用substr()函数：

$data = "";
while($row = mysql_fetch_array($result)) {
    $data .= "['$row[keyword]', $row[jumlah]],<br>";
}
$data = substr($data, 0, -5);
echo $data;

Answer 3

里姆()：

$data = rtrim($data, ',');

或者，在您的特定示例中，substr：

$data = substr($data, 0, -5);

移除“

“”也是。