期望在登录提示下发送$expect_out(缓冲区)

Question

Expect是在提示输入用户凭据时发送$expect_out(缓冲区)，而不是指定变量($user)。然后就超时了。以下是代码：

...
    }
    "yes" {
        send_user "\nEnter your username for the WLC supporting the new APs:\n"
        sleep 6
    }
}
expect {
    -re "(.*)\n" {
        set user $expect_out(1,string)
    }
}
send_user "\nEnter your password for the WLC supporting the new APs:\n"
sleep 15
expect {
    -re "(.*)\n" {
        set pass $expect_out(1,string)
    }
}
sleep 1
send_user "\nSshing to the IP of the WLC supporting the new APs ($wlc_temp)\n"
spawn ssh $wlc_temp

expect {
    "User:" {
        send $user\n
        sleep 1
    }
}
expect {
    "assword:" {
        send $pass\n
        sleep 1
    }
}

结果如下：

用户：(设备主机名)用户：

以下是首次亮相：

支持新的APs ()派生ssh父级的WLC的IP :等待同步字节父级:告诉子进程前进，父级:现在与子生成不同步:返回{7153} expect："“(spawn_id exp6)是否与”用户：“匹配？不是 expect："\r\n“(spawn_id exp6)与glob模式"User:”匹配吗？否(设备主机名)用户： expect：“\r\n(设备主机名) User:”(spawn_id exp6)与glob模式"User:“匹配吗？是的: set expect_out(0，string) "User:“expect: set expect_out(spawn_id) " exp6”expect: set expect_out(缓冲区)“\r\n(设备主机名)用户：”发送:发送"\n“到{exp6} 预期：“”(spawn_id exp6)匹配单词"assword:“吗？不是 (设备主机名)用户： expect：“\r\n(设备主机名)用户：”(spawn_id exp6)与glob模式"assword:“匹配吗？没有期望:超时

更新：将请求用户输入的语句重新定位到脚本的顶部，作为一项工作。

Answer 1

当您想从用户读取输入时，应该使用expect_user而不是expect。

        send_user "\nEnter your username for the WLC supporting the new APs:\n"
        sleep 6
    }
}
expect_user {
    -re "(.*)\n" {
        set user $expect_out(1,string)
    }
}
send_user "\nEnter your password for the WLC supporting the new APs:\n"
sleep 15
expect_user {
    -re "(.*)\n" {
        set pass $expect_out(1,string)
    }
}
sleep 1
send_user "\nSshing to the IP of the WLC supporting the new APs ($wlc_temp)\n"

# ...

(我还认为可以在其中使用更少的sleep调用，而只是调整超时，但这不太可能对脚本的正确操作产生影响。)