Python加密

Question

由于我对Java的不完全了解，我很难将这些加密代码转换为Python代码。两者应该有完全相同的结果。我们将非常感谢您的帮助。

Java函数

import javax.crypto.Cipher;
import javax.crypto.spec.SecretKeySpec;
import java.security.Key;


class Main
{
    public static void main (String[] args) throws java.lang.Exception
    {
        String s = "testings";
        Cipher cipher = Cipher.getInstance("Blowfish/ECB/PKCS5Padding");
        Key key = new SecretKeySpec("6#26FRL$ZWD".getBytes(), "Blowfish");
        cipher.init(1, key);
        byte[] enc_bytes = cipher.doFinal(s.getBytes());
        System.out.println(enc_bytes);
    }
}

Python等效

def PKCS5Padding(string):
    byteNum = len(string)
    packingLength = 8 - byteNum % 8
    if packingLength == 8:
        return string
    else:
        appendage = chr(packingLength) * packingLength
        return string + appendage

def PandoraEncrypt(string):
    from Crypto.Cipher import Blowfish
    key = b'6#26FRL$ZWD'
    c1  = Blowfish.new(key, Blowfish.MODE_ECB)
    packedString = PKCS5Padding(string)
    return c1.encrypt(packedString)

结果

Java函数：“？？”

Python函数：“4A-`*‘*’”

Answer 1

使用您的示例，我为python和Java获得了相同的输出。

爪哇：

import java.math.BigInteger;
import java.security.Key;

import javax.crypto.Cipher;
import javax.crypto.spec.SecretKeySpec;

public class Blowfish1 {

    public static void main(String[] args) throws Exception {
        String s = "testings";
        Cipher cipher = Cipher.getInstance("Blowfish/ECB/PKCS5Padding");
        Key key = new SecretKeySpec("6#26FRL$ZWD".getBytes(), "Blowfish");
        cipher.init(Cipher.ENCRYPT_MODE, key);
        byte[] enc_bytes = cipher.doFinal(s.getBytes());
        System.out.printf("%x%n", new BigInteger(1, enc_bytes));
    }

}

Python：

from Crypto.Cipher import Blowfish
import binascii

# See @falsetru answer for the following method
#
def PKCS5Padding(string):
    byteNum = len(string)
    packingLength = 8 - byteNum % 8
    appendage = chr(packingLength) * packingLength
    return string + appendage

def PandoraEncrypt(string):
    key = b'6#26FRL$ZWD'
    c1  = Blowfish.new(key, Blowfish.MODE_ECB)
    packedString = PKCS5Padding(string)
    return c1.encrypt(packedString)

if __name__ == '__main__':
    s = 'testings'
    c = PandoraEncrypt(s)
    print(binascii.hexlify(c))

在这两种情况下，输出都是223950ff19fbea872fce0ee543692ba7

Answer 2

def PKCS5Padding(string):
    byteNum = len(string)
    packingLength = 8 - byteNum % 8
    appendage = chr(packingLength) * packingLength
    return string + appendage

用chr代替str。

>>> chr(1)
'\x01'
>>> str(1)
'1'

str * int ->重复str

>>> '!' * 5
'!!!!!'