我有两个代码(程序)
程序1:
//global variables
MYSQL_RES *res_set;
MYSQL_ROW row;
MYSQL *connect;
int main()
{
connect=mysql_init(NULL);
mysql_real_connect(connect, NULL, "root", "suvp" ,"Employees" ,0,NULL,0);
/*Other Code*/
mysql_free_result(res_set);
mysql_close(connect);
}"Other Code“包含一个for循环,它调用使用相同res_set存储来自mysql_store_result的结果的函数。正如所见,我只在main末尾调用mysql_free_result(res_set);一次。
valgrind显示了上述情况下的still reachable内存问题(我选择忽略这个问题)。没有其他泄漏。
程序2:
类mysqlClientClass有以下私有变量,
MYSQL *connect;
MYSQL_RES *res_set;
MYSQL_ROW row;其中一些方法(与我的问题相关),
mysqlClientClass::~mysqlClientClass()
{
if(connect!=NULL)
{
mysql_free_result(res_set);
mysql_close(connect);
}
}如果用户未能调用closeConnection,析构函数将关闭它(通过检查connect是否设置为NULL或否)
void mysqlClientClass::closeConnection()
{
mysql_free_result(res_set);
mysql_close(connect);
connect = NULL;
}getResults是整个代码中唯一使用mysql_store_result的方法。
void mysqlClientClass::getResults(string iQuery)
{
/* form query
execute Query */
res_set = mysql_store_result(connect);
/* Do other things */
mysql_free_result(res_set); // ------------------------>
res_set = NULL;
}
}如果我没有在函数的末尾释放res_set (并且只在析构函数/ close Connection中释放它),并且对这个函数进行几次调用,
=10162== LEAK SUMMARY:
==10162== definitely lost: 312 bytes in 3 blocks
==10162== indirectly lost: 49,152 bytes in 9 blocks
==10162== possibly lost: 0 bytes in 0 blocks
==10162== still reachable: 73,872 bytes in 21 blocks
==10162== suppressed: 0 bytes in 0 blocks
==10162== Reachable blocks (those to which a pointer was found) are not shown.
==10162== To see them, rerun with: --leak-check=full --show-reachable=yes
==10162==
==10162== For counts of detected and suppressed errors, rerun with: -v
==10162== ERROR SUMMARY: 3 errors from 3 contexts (suppressed: 0 from 0)这一切都归结为mysql_store_result
==10162== by 0x406C3CA: mysql_store_result (in /usr/lib/i386-linux-gnu/libmysqlclient.so.18.0.0)
==10162== by 0x8048E03: mysqlClientClass::getResults(std::string) (mysqlClientClass.cpp:103)根据mysql_store_result的mysql_store_result页面
mysql_store_result()将查询的整个结果读入客户端,为分配MYSQL_RES结构,并将结果放入该结构。
它还建议我应该在使用后调用free_result。
程序2(当我不调用mysql_free_result**) 时内存泄漏,但是为什么程序1没有显示任何泄漏呢?)在程序1中,我也会在不同函数之间调用** mysql_store_result ,而不需要每次释放。。
发布于 2013-06-26 02:17:02
您不需要mysql_store_result从查询中获取数据--使用sqlite3_exec回调
int ListDataCallback(void *pArg, int argc, char **argv, char **columnNames){
//cast pArg to your user data pointer
//argc - count of columns in the result
//argv - a result field as string
return 0;
}
void get_data()
{
char *selectErrMsgP = NULL;
int err = sqlite3_exec( database, selectQ, ListDataCallback, (void*)myUserData, &selectErrMsgP );
if( err ) {
//handle error
}
}从未有过这种方法的任何漏洞
https://stackoverflow.com/questions/16806704
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