所以我用的是微型剖析器,它给了我一些很好的统计数据。
然而,我注意到的一件事是,我得到了很多SQL调用的最小值,现在最大的事情是呈现各种部分和HTML。
例如,以下是我所面临的两个不同问题的例子:
Mini-Profiler
GET http://localhost:3000/ 14.0 +0.0
Executing action: index 9.5 +9.0
Rendering: home/index 7.8 +16.0
Rendering: home/_row 7.9 +22.0
Rendering: layouts/application 1038.7 +32.0
Rendering: layouts/_navigation 6.0 +586.0Development.log
Started GET "/" for 127.0.0.1 at 2013-05-17 18:00:26 -0500
Processing by HomeController#index as HTML
Item Load (0.6ms) SELECT "items".* FROM "items" WHERE "items"."is_approved" = 't'
ActsAsTaggableOn::Tag Load (0.6ms) SELECT "tags".* FROM "tags" INNER JOIN "taggings" ON "tags"."id" = "taggings"."tag_id" WHERE "taggings"."taggable_id" = 13 AND "taggings"."taggable_type" = 'Item' AND (taggings.context = 'tags' AND taggings.tagger_id IS NULL)
Rendered home/_row.html.erb (8.0ms)
Rendered home/index.html.erb within layouts/application (15.7ms)
Rendered layouts/_social_media.html.erb (0.5ms)
(0.4ms) SELECT items.id FROM "items"
ActsAsTaggableOn::Tag Load (0.7ms) SELECT tags.*, taggings.tags_count AS count FROM "tags" JOIN (SELECT taggings.tag_id, COUNT(taggings.tag_id) AS tags_count FROM "taggings" INNER JOIN items ON items.id = taggings.taggable_id WHERE (taggings.taggable_type = 'Item' AND taggings.context = 'tags') AND (taggings.taggable_id IN(13)) GROUP BY taggings.tag_id HAVING COUNT(taggings.tag_id) > 0) AS taggings ON taggings.tag_id = tags.id ORDER BY count LIMIT 5
Rendered layouts/_navigation.html.erb (6.1ms)
Rendered layouts/_site_nav.html.erb (0.6ms)
Rendered layouts/_messages.html.erb (0.2ms)
Rendered layouts/_footer.html.erb (0.1ms)
Completed 200 OK in 1069ms (Views: 1066.0ms | ActiveRecord: 2.3ms)从顶部的Mini输出,显示主application.html.erb显著增加了加载时间。
这里是另一个应用程序的另一个例子,其中视图是花费最多时间呈现的:
Started GET "/" for 127.0.0.1 at 2013-05-17 17:55:01 -0500
User Load (0.2ms) SELECT "users".* FROM "users" WHERE "users"."id" = 1 LIMIT 1
Processing by HomeController#index as HTML
Category Load (0.2ms) SELECT "categories".* FROM "categories" LIMIT 6
Banner Load (0.2ms) SELECT "banners".* FROM "banners" INNER JOIN "banner_types" ON "banner_types"."id" = "banners"."banner_type_id" WHERE (banner_types.name = 'Featured')
Banner Load (0.2ms) SELECT "banners".* FROM "banners" INNER JOIN "banner_types" ON "banner_types"."id" = "banners"."banner_type_id" WHERE (banner_types.name = 'Side')
Product Load (0.3ms) SELECT "products".* FROM "products"
Vendor Load (0.3ms) SELECT "vendors".* FROM "vendors" WHERE "vendors"."id" IN (12, 11, 10)
Vendor Load (0.2ms) SELECT "vendors".* FROM "vendors"
User Load (0.2ms) SELECT "users".* FROM "users"
Rendered home/_popular_products.html.erb (16.1ms)
Rendered home/_popular_stores.html.erb (2.4ms)
Rendered home/index.html.erb within layouts/application (26.4ms)
Piggybak::Sellable Load (0.2ms) SELECT "sellables".* FROM "sellables" WHERE "sellables"."id" = 1 LIMIT 1
Rendered layouts/_login_nav.html.erb (8.2ms)
Rendered layouts/_navigation.html.erb (0.8ms)
CACHE (0.0ms) SELECT "vendors".* FROM "vendors"
Rendered layouts/_store_dropdown.html.erb (2.2ms)
Rendered layouts/_header.html.erb (18.1ms)
Rendered layouts/_messages.html.erb (0.3ms)
Rendered layouts/_footer.html.erb (0.9ms)
Completed 200 OK in 242ms (Views: 209.8ms | ActiveRecord: 1.9ms)当然,这个特定的时间只是209.8ms,但是在不同的加载时间,它都和5,000ms一样高。
如何优化这些视图和部分的呈现?或者,我能用什么工具至少找出是什么导致了长时间的负载,这样我才能慢慢地处理掉它呢?
发布于 2013-05-17 23:17:13
在第二个示例中,我看到了对以下方面的查询:
如果您的部分必须迭代大量的对象集合,它将大大降低呈现时间。
注意调用集合(如Vendor.all.each do |v| )的迭代器。不应在视图中调用模型类方法。在所需对象的控制器中构建一个集合,然后发送到实例变量中的视图。
https://stackoverflow.com/questions/16619095
复制相似问题