在嵌套for循环("*")之前打印while循环(1，10)

Question

我正在尝试用编写代码来记录用户玩骰子游戏“中间”的结果，然后在游戏结束时打印滚动的统计数据，所以我想要打印的基本上是这样的。

Game Summary
============
You played 3 Games:
|--> Games won: 0
|--> Games lost: 3

Dice Roll Stats:
Face Frequency
1
2 *
3
4 **
5 *
6 *
7
8 *
9 *
10 **
Thanks for playing!

当“*”被永远打印出来的时候，死去的脸被滚动了，然而我却一直以这样的方式结束。

Game Summary
============

You played a total of 3 games:
|--> Games won: 1
|--> Games lost: 2

Dice Roll Stats.

Face  Frequency
 1
 2
 ** 3
 4
 5
 * 6
 * 7
 **** 8
 * 9
 10
 Thanks for playing!

因此，我想要做的是将‘*’垂直排列，并与索引值(1，10)相同，而不是总是将‘*’放在索引值的前面。

die1 = random.randint(1, 10)
dieCount[die1] = dieCount[die1] + 1
die2 = random.randint(1, 10)
dieCount[die2] = dieCount[die2] + 1
die3 = random.randint(1, 10)
dieCount[die3] = dieCount[die3] + 1
dieCount = [0,0,0,0,0,0,0,0,0,0,0]
index = 1
while index < len(dieCount):

    print(index)
    for n in range(dieCount[index]):   
        print('*', end='')
    index = index + 1

Answer 1

你可以用这种方式打印整条线：

for i, val in enumerate(dieCount[1:], 1):
    print('{} {}'.format(i, '*' * val))

Answer 2

第一个打印(索引)似乎是自动添加后的换行符。试着把它写成你打印*的方式：

    print(index, end='')

Answer 3

试试这个：

while index < len(dieCount):

    print(index,end ="")
    for n in range(dieCount[index]):   
        print('*', end='')
    print()
    index = index + 1