检查员工的电子邮件是否包含他的名字？？不区分大小写。

Question

当员工姓名包含在电子邮件中时，我想显示与其相关的名称和电子邮件。用户可以有多个电子邮件。

employee
id   name 
1    Steve Been
2    Rob Kem
3    Bob Kimi

Emails
emplyee_id email
1          steve@domain.com
1          007@domain.com
1          Been@domain.com
2          Robkem@domain.com 
2          Rob.Kem@domain.com 
3          Boooob@domain.com
3          kimi@domain.com   

查询不应该区分大小写。，我希望这个查询能显示如下内容：

name            email
Steve Been      steve@domain.com
Steve Been      Been@domain.com
Rob Kem         Robkem@domain.com 
Rob Kem         Rob.Kem@domain.com       
Bob Kimi        kimi@domain.com

我试过了，但是输出是空的：

select empl.Name as 'employee Name', em.email as 'Product Name'

from email em JOIN employee empl
ON em.employee_id = empl.ID

WHERE FIND_IN_SET(LOWER(empl.Name),LOWER(em.Name))

Answer 1

试一试

SELECT e.name,
       m.email
  FROM emails m JOIN
       employee e ON m.emplyee_id = e.id
 WHERE INSTR(m.email, SUBSTRING_INDEX(e.name, ' ', 1)) > 0 
    OR INSTR(m.email, SUBSTRING_INDEX(e.name, ' ', -1)) > 0

SQLFiddle

INSTR()是不区分大小写的，除非其中一个刺是二进制字符串，但是您总是可以为一个好的度量添加LOWER()。

UPDATE:根据您的附加请求，您可以使用这样的查询来完成此任务

SELECT name, 
       total, 
       matched, 
       total - matched unmatched
  FROM (
SELECT e.name,
       COUNT(*) total,
       SUM(CASE WHEN INSTR(m.email, SUBSTRING_INDEX(e.name, ' ', 1)) > 0 
                  OR INSTR(m.email, SUBSTRING_INDEX(e.name, ' ', -1)) THEN 1 ELSE 0 END) matched
  FROM emails m JOIN
       employee e ON m.emplyee_id = e.id
 GROUP BY e.id, e.name) q

SQLFiddle