打印格式Java

Question

 out.append("Line " + (j+1) + ": ");  
 System.out.print("Line " + (j+1) + ":");
 for (int i = 0; i < lotto.length;i++){
     lotto[i] = r.nextInt(45)+1;                                                                
     out.append(lotto[i] + " ");
     System.out.print(lotto[i] + " ");
 }

现在它正在按以下方式打印

第1行: 41 7 38 20 38 39线2: 12 35 5 27 4 33线3: 9 3 10 15 35 2

Answer 1

因为您正在打印Line n之后的新行。

您应该在打印数字的内部println之后使用for。

喜欢

// print "Line n"
System.out.print("Line " + (j+1) + ":");

for (int i = 0; i < lotto.length;i++){
    lotto[i] = r.nextInt(45)+1;                                                             
    out.append(lotto[i] + " ");
    // Print in the same line the numbers
    System.out.print(lotto[i] + " ");
}
// Print the new line
System.out.println();