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社区首页 >问答首页 >基于SWT/Jface的SWT表交换

基于SWT/Jface的SWT表交换
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Stack Overflow用户
提问于 2013-04-08 05:42:03
回答 1查看 111关注 0票数 0

我有一个表,当应用程序启动时,它会被加载。此表是在复合中创建的。现在,我有了另一个函数搜索按钮,它将基于搜索输入填充相同的表。我无法用搜索结果填充表。是否可以根据使用SWT/Jface的功能(加载应用程序启动/search结果)在同一表中进行切换。例如,在应用程序启动时显示表值

代码语言:javascript
复制
 m_workplaceViewer = new TableViewer(table);


               String[] workplace_titles= new String[]{"Code","Plant","Compy Reg Num","Num Of Employees","Type of industry","Type of products/service", "Representative","Main Phone","Phone 1","Phone 2","Fax", "Zip Code",
                        "Address 1","Address 2","Email","HomePage","Note 1","Note 2","Note 3","Note 4","Note 5"};


                for (int i = 0; i < 21; i++){

                 TableViewerColumn column_workplace = new TableViewerColumn(m_workplaceViewer,
                         SWT.NONE);                     
                column_workplace.getColumn().setWidth(75);
                column_workplace.getColumn().setText(workplace_titles[i]);              

               }   

                try {
                    workplaceDetailList= workplaceDaoImpl.getWorkplaceDetails();
                } catch (SQLException e3) {
                    // TODO Auto-generated catch block
                    e3.printStackTrace();
                }

搜索按钮

代码语言:javascript
复制
btnSearch.addListener(SWT.Selection, new Listener() {
                    public void handleEvent(Event event) {

                        String plant=text_workplace.getText();
                        System.out.println("Select Me : " + plant);

                        IStructuredSelection selection = (IStructuredSelection) m_workplaceViewer
                                .getSelection();
                        if (selection.getFirstElement() instanceof WorkplaceDetail) {
                         workplaceDetail = (WorkplaceDetail) selection.getFirstElement();
                        }
                         System.out.println("Start Search--2");

                        if (plant!=""){ 
                             table.removeAll();
                            workplaceDetailList=workplaceDaoImpl.getWorkplaceDetailsSearchByPlant(plant);

m_workplaceViewer.setInput(workplaceDetailList)

代码语言:javascript
复制
                            }           

数据库:

代码语言:javascript
复制
 ObservableListContentProvider m_personViewerContentProviderList1 = new ObservableListContentProvider();
             m_workplaceViewer.setContentProvider(m_personViewerContentProviderList1);

             IObservableList input = 
                       Properties.selfList(WorkplaceDetail.class).observe(workplaceDetailList);
            m_workplaceViewer.setInput(input);  

             ViewerSupport.bind(m_workplaceViewer,
                     input,
                    BeanProperties.values(new String[] {"code","plant","compRegNum","numOfEmps","typeIndst",
                            "typeProd","employee.empName","address.mainPhone","address.phone1","address.phone2",
                            "address.fax", "address.zip", "address.add1", "address.add2","address.empEmail",
                            "address.homepage","note1", "note2", "note3", "note4", "note5"}));

请不要说我只有一张桌子。

EN

回答 1

Stack Overflow用户

发布于 2013-04-08 06:19:38

通常的解决办法是

  • 每当您想要显示新的结果时,请调用view.setInput(...)
  • 在这两种情况下都使用IObservableList作为中间结果列表,然后只要操作列表就可以随时替换列表的内容。
  • ViewFilter上使用TableViewer --尽管只有当搜索结果是初始内容的适当子集时,才能使用此方法

我通常使用后一种方法,主要是因为我可以将UI与业务逻辑完全分离开来,这可以使应用程序更容易测试:-)

票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/15872003

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