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Question

我的下一个任务是修改当前代码。在之前的练习中，我已经编写了一个基本的应用程序，它涵盖了一个数字猜测游戏。守则如下：

# Guess My Number
#
# The computer picks a random number between 1 and 100
# The player tries to guess it and the computer lets
# the player know if the guess is too high, too low
# or right on the money

import random  

print("\tWelcome to 'Guess My Number'!")
print("\nI'm thinking of a number between 1 and 100.")
print("Try to guess it in as few attempts as possible.\n")

# set the initial values
the_number = random.randint(1, 100)
guess = int(input("Take a guess: "))
tries = 1

# guessing loop
while guess != the_number:
    if guess > the_number:
        print("Lower...")
    else:
        print("Higher...")

    guess = int(input("Take a guess: "))
    tries += 1

print("You guessed it!  The number was", the_number)
print("And it only took you", tries, "tries!\n")

input("\n\nPress the enter key to exit.")

我的任务是对此进行修改，以便在向用户发送失败消息之前有一定数量的so。到目前为止，这一章已经涵盖了"if，elif，else，for，循环，避免无限循环“。因此，我只想限制我对这些概念的反应。For循环将在下一章中讨论。

我试过什么？

到目前为止，我已经尝试在另一个while循环中使用5 to和to变量来修改这个块，但是它似乎不起作用。

# guessing loop
while tries < 6:
    guess = int(input("Take a guess: "))
    if guess > the_number:
        print("Lower...")
    elif guess < the_number:
        print("Higher...")
    elif guess == the_number:
        print("You guessed it!  The number was", the_number)
        print("And it only took you", tries, "tries!\n")
    break
    tries += 1

input("You didn't do it in time!")
input("\n\nPress the enter key to exit.")

任何提示或突出说明我错过了什么，将不胜感激，以及任何解释，我错过了什么。教自己编程思考也是很棘手的。

当我运行不工作的时，循环条件似乎不起作用。我的空闲反馈如下。

这意味着我的问题可以概括为我的循环逻辑在哪里被打破了？

>>> ================================ RESTART ================================
>>> 
    Welcome to 'Guess My Number'!

I'm thinking of a number between 1 and 100.
Try to guess it in as few attempts as possible.

Take a guess: 2
Take a guess: 5
Higher...
You didn't do it in time!


Press the enter key to exit.

Answer 1

问题在于您的break语句没有缩进以包含在elif中。

elif guess == the_number:
    print("You guessed it!  The number was", the_number)
    print("And it only took you", tries, "tries!\n")
break

因此，循环总是在第一次迭代之后停止。缩进要包含在break中的elif，它应该可以工作。

Answer 2

中断不在条件中。在它之前添加一个选项卡。