如何使用元组访问深度嵌套的字典？

Question

我想扩展一下the autovivification example，在nosklo给出的一个先前的答案中，允许通过元组访问字典。

nosklo的解决方案如下所示：

class AutoVivification(dict):
    """Implementation of perl's autovivification feature."""
    def __getitem__(self, item):
        try:
            return dict.__getitem__(self, item)
        except KeyError:
            value = self[item] = type(self)()
            return value

测试：

a = AutoVivification()

a[1][2][3] = 4
a[1][3][3] = 5
a[1][2]['test'] = 6

print a

输出：

{1: {2: {'test': 6, 3: 4}, 3: {3: 5}}}

在这种情况下，我希望设置一个节点，给定一些任意的下标元组。如果我不知道元组有多少层深，我如何设计一种方法来设置适当的节点？

我在想，也许我可以使用如下语法：

mytuple = (1,2,3)
a[mytuple] = 4

但我想不出一个可行的方法。

更新

基于@JCash的回答，我有一个充分发挥作用的例子：

class NestedDict(dict):
    """                                                                       
    Nested dictionary of arbitrary depth with autovivification.               

    Allows data access via extended slice notation.                           
    """
    def __getitem__(self, keys):
        # Let's assume *keys* is a list or tuple.                             
        if not isinstance(keys, basestring):
            try:
                node = self
                for key in keys:
                    node = dict.__getitem__(node, key)
                return node
            except TypeError:
            # *keys* is not a list or tuple.                              
                pass
        try:
            return dict.__getitem__(self, keys)
        except KeyError:
            raise KeyError(keys)
    def __setitem__(self, keys, value):
        # Let's assume *keys* is a list or tuple.                             
        if not isinstance(keys, basestring):
            try:
                node = self
                for key in keys[:-1]:
                    try:
                        node = dict.__getitem__(node, key)
                    except KeyError:
                        node[key] = type(self)()
                        node = node[key]
                return dict.__setitem__(node, keys[-1], value)
            except TypeError:
                # *keys* is not a list or tuple.                              
                pass
        dict.__setitem__(self, keys, value)

它可以使用扩展片表示法实现与上面相同的输出：

d = NestedDict()
d[1,2,3] = 4
d[1,3,3] = 5
d[1,2,'test'] = 6

Answer 1

这似乎很管用

def __setitem__(self, key, value):
    if isinstance(key, tuple):
        node = self
        for i in key[:-1]:
            try:
                node = dict.__getitem__(node, i)
            except KeyError:
                node = node[i] = type(self)()
        return dict.__setitem__(node, i, value)
    return dict.__setitem__(self, key, value)