json语法分析错误

Question

请帮我找出这段代码中的错误。我想通过json从远程服务器(php & mysql)获取一些数据，然后解析它，问题是结果返回空，但是它应该在这个链接：example.php处返回名称

package com.shadatv.shada;

import java.io.IOException;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.widget.TextView;
import android.widget.Toast;

public class canticlesActivity extends Activity {

    TextView httpStuff;
    HttpClient client;
    JSONObject json;

    final static String URL = "http://codeincloud.tk/json_android_example.php";
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.canticles);

        httpStuff = (TextView) findViewById(R.id.textView1);
        client = new DefaultHttpClient();
        new Read().execute("name");
    }

    public JSONObject lastTweet() throws ClientProtocolException, IOException, JSONException {
        StringBuilder url = new StringBuilder(URL);

        HttpGet get = new HttpGet(url.toString());
        HttpResponse r = client.execute(get);
        int status = r.getStatusLine().getStatusCode();

        if (status == 200) {
            HttpEntity e = r.getEntity();
            String data = EntityUtils.toString(e);
            JSONArray timeline = new JSONArray(data);
            JSONObject last = timeline.getJSONObject(0);
            return last;

        } else {
            Toast.makeText(getBaseContext(), "error", Toast.LENGTH_SHORT);
            return null;
        }
    }

    public class Read extends AsyncTask<String, Integer, String>{

        @Override
        protected String doInBackground(String... params) {
            // TODO Auto-generated method stub

            try {
                json = lastTweet();
                return json.getString(params[0]);
            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return null;
        }

        @Override
        protected void onPostExecute(String result) {
            // TODO Auto-generated method stub
            Toast.makeText(getBaseContext(), "ahmed .. " + result, Toast.LENGTH_LONG).show();
            httpStuff.setText(result);
        }

    }
}

Answer 1

复制和过去，现在，它正在工作。我更改了JSONObject last =新的JSONObject(data)；

因为example.php重新调整了一个JSONObject

package com.shadatv.shada;

import java.io.IOException;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.widget.TextView;
import android.widget.Toast;

public class canticlesActivity extends Activity {

    TextView httpStuff;
    HttpClient client;
    JSONObject json;

    final static String URL = "http://codeincloud.tk/json_android_example.php";
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.canticles);

        httpStuff = (TextView) findViewById(R.id.textView1);
        client = new DefaultHttpClient();
        new Read().execute("name");
    }

    public JSONObject lastTweet() throws ClientProtocolException, IOException, JSONException {
        StringBuilder url = new StringBuilder(URL);

        HttpGet get = new HttpGet(url.toString());
        HttpResponse r = client.execute(get);
        int status = r.getStatusLine().getStatusCode();

        if (status == 200) {
            HttpEntity e = r.getEntity();
            String data = EntityUtils.toString(e);

            JSONObject last =  new JSONObject(data);
            return last;

        } else {
            Toast.makeText(getBaseContext(), "error", Toast.LENGTH_SHORT);
            return null;
        }
    }

    public class Read extends AsyncTask<String, Integer, String>{

        @Override
        protected String doInBackground(String... params) {
            // TODO Auto-generated method stub

            try {
                json = lastTweet();
                return json.getString(params[0]);
            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return null;
        }

        @Override
        protected void onPostExecute(String result) {
            // TODO Auto-generated method stub
            Toast.makeText(getBaseContext(), "ahmed .. " + result, Toast.LENGTH_LONG).show();
            httpStuff.setText(result);
        }

    }
}

Answer 2

将当前的json字符串解析为：

 HttpEntity e = r.getEntity();
 String data = EntityUtils.toString(e);
 // convert data to json object
 JSONObject last =new JSONObject(data);

因为当前的webservice仅重新运行一个JSONObject而不是JSONArray

Answer 3

更好的方法是使用，这比手工解析要简单得多。

库的链接是：http://code.google.com/p/google-gson/