下面的代码试图调整reportlab Platypus可流动文本的字体大小,直到它符合我给它的可用高度。但是我发现,可流动的段落并没有在递归的每个循环中保存它的style.fontSize属性,而且python具有无限递归。
def fits_space(w,h,aW,aH,p):
"""
Determines if inputted text fits in the space given for a paragraph
and if it doesn't, reduces the font-size until it does.
"""
if w<=aW and h<=aH:
# return font size to apply it to the para again
print "final font_size: %d" % p.style.fontSize
return p # now render the paragraph in the doctemplate
else:
p.style.fontSize -= 1
w,h = p.wrap(aW, aH)
fits_space(w,h,aW,aH,p)
def renderPage(name, text):
doc = SimpleDocTemplate("%s.pdf" % name)
parts = []
style = ParagraphStyle(name='fancy')
style.fontSize = 150
p = Paragraph(text, style)
aW = PAGE_WIDTH-4*inch # available width and height
aH = PAGE_HEIGHT-4*inch
w,h = p.wrap(aW, aH) # find required space
p = fits_space(w,h,aW,aH,p) # recursively fit the font size to the text
parts.append(p)
doc.build(parts)谁能让我知道为什么-在fits_space()函数中,在else子句中,当我调用p.wrap(aW,aH)时,输出的值与我将段落的fontSize减少1时相同?如果我缩小字体大小,那么包装的高度肯定会更小吗?
知道我哪里出问题了吗?
在我的示例中,UPDATE Nitzie的代码几乎可以工作,只需要向style.leading添加一个大小调整器:
def shrink_font_size(aW, aH, text, style):
"""Shrinks font size by using pdfmetrics to calculate the height
of a paragraph, given the font name, size, and available width."""
def break_lines(text, aW):
# simpleSplit calculates how reportlab will break up the lines for
# display in a paragraph, by using width/fontsize.
return simpleSplit(text, style.fontName, style.fontSize, aW)
def line_wrap(lines, style):
# Get overall width of text by getting stringWidth of longest line
width = stringWidth(max(lines), style.fontName, style.fontSize)
# Paragraph height can be calculated via line spacing and number of lines.
height = style.leading * len(lines)
return width, height
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
while height > aH or width > aW:
style.fontSize -= 1
style.leading -= 1 # do this if you're leading is based on the fontSize
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)提亚
发布于 2013-02-06 03:11:48
由于某些原因,一旦您在调用了fontsize一次之后更改了fontsize,p.wrap似乎不会真正重新计算它的高度/宽度。
通过计算基于ReportLab的stringWidth和splitLines方法的字体大小,我获得了一个工作版本。尽管这意味着它不再是递归的:
from reportlab.platypus import SimpleDocTemplate
from reportlab.lib.styles import ParagraphStyle
from reportlab.lib.units import inch
from reportlab.lib.pagesizes import A4
from reportlab.platypus import Paragraph
from reportlab.lib.utils import simpleSplit
from reportlab.pdfbase.pdfmetrics import stringWidth
def shrink_font_size(aW, aH, text, style):
"""Shrinks font size by using pdfmetrics to calculate the height
of a paragraph, given the font name, size, and available width."""
def break_lines(text, aW):
# simpleSplit calculates how reportlab will break up the lines for
# display in a paragraph, by using width/fontsize.
return simpleSplit(text, style.fontName, style.fontSize, aW)
def line_wrap(lines, style):
# Get overall width of text by getting stringWidth of longest line
width = stringWidth(max(lines), style.fontName, style.fontSize)
# Paragraph height can be calculated via line spacing and number of lines.
height = style.leading * len(lines)
return width, height
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
while height > aH or width > aW:
style.fontSize -= 1
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
def renderPage(name, text):
doc = SimpleDocTemplate("%s.pdf" % name)
parts = []
# Wasn't sure where PAGE_WIDTH and PAGE_HEIGHT came from for OP,
# so I just used a standard A4 page measurement.
PAGE_WIDTH, PAGE_HEIGHT = A4
aW = PAGE_WIDTH - 4*inch # available width and height
aH = PAGE_HEIGHT - 4*inch
style = ParagraphStyle(name='fancy')
style.fontSize = 200
style.leading = 20
shrink_font_size(aW, aH, text, style)
p = Paragraph(text, style)
parts.append(p)
doc.build(parts)
if __name__ == "__main__":
renderPage('test', '12345689019283382848248284 842828428529392381472754 842828428529392381472754 842828428529392381472754\n' * 10)https://stackoverflow.com/questions/14719194
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