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社区首页 >问答首页 >php curl可以从facebook下载多张照片(压缩)

php curl可以从facebook下载多张照片(压缩)
EN

Stack Overflow用户
提问于 2013-01-19 13:09:17
回答 1查看 1K关注 0票数 0

我使用curl为授权用户从Facebook url获取照片,对于每一张照片,我将其添加到zip文件中,允许用户以zip方式下载整个相册。

代码语言:javascript
复制
 if( !isset($_GET['id']) )
die("No direct access allowed!");
    require 'facebook.php';
  $facebook = new Facebook(array(
'appId'  => 'removed',
'secret' => 'removed',
'cookie' => true,
));

if( !isset($_GET['id']) )
die("No direct access allowed!");
    $params = array();
    if( isset($_GET['offset']) )
        $params['offset'] = $_GET['offset'];
    if( isset($_GET['limit']) )
        $params['limit'] = $_GET['limit'];
    $params['fields'] = 'name,source,images';
    $params = http_build_query($params, null, '&');
    $album_photos = $facebook->api("/{$_GET['id']}/photos?$params");
    if( isset($album_photos['paging']) ) {
        if( isset($album_photos['paging']['next']) ) {
            $next_url = parse_url($album_photos['paging']['next'], PHP_URL_QUERY) . "&id=" . $_GET['id'];
        }
        if( isset($album_photos['paging']['previous']) ) {
            $pre_url = parse_url($album_photos['paging']['previous'], PHP_URL_QUERY) . "&id=" . $_GET['id'];
        }
    }
    $photos = array();
    if(!empty($album_photos['data'])) {
        foreach($album_photos['data'] as $photo) {
            $temp = array();
            $temp['id'] = $photo['id'];
            $temp['name'] = (isset($photo['name'])) ? $photo['name']:'photo_'.$temp['id'];
            $temp['picture'] = $photo['images'][1]['source'];
            $temp['source'] = $photo['source'];
            $photos[] = $temp;
        }
    }
    ?>
<?php if(!empty($photos)) { ?>
<?php
$zip = new ZipArchive();


$tmp_file =tempnam('.','');
$file_opened=$zip->open($tmp_file, ZipArchive::CREATE);


foreach($photos as $photo) {
    $url=$photo['source'];
    $ch = curl_init($url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    $download_file=curl_exec($ch);
    #add it to the zip
    $file_added=$zip->addFile($download_file);
}

    # close zip
    $zip->close();

    # send the file to the browser as a download
    header('Content-Description: File Transfer');
    header('Content-Type: application/force-download');
    header('Content-Disposition: attachment; filename="albums.zip"');
    header('Content-Transfer-Encoding: binary');
    header('Expires: 0');
    header('Cache-Control: must-revalidate');
    header('Pragma: public');
    header('Content-Length: ' . filesize($tmp_file));
    ob_clean();
    flush();
    readfile($tmp_file);
    exit;
 } ?>

问题: zip->open创建一个文件,zip->add为添加的每个文件返回1,但zip大小仍然为0,并且readfile不提示下载。

EN

回答 1

Stack Overflow用户

发布于 2013-01-19 14:07:04

现在,你正在尝试这样做:

代码语言:javascript
复制
foreach ($photos as $photo) {
    $url = $photo['source'];
    $ch = curl_init($url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    $download_file = curl_exec($ch);
    $file_added = $zip->addFile($download_file);
}

这将无法工作,因为$dowload_file字符串,而不是文件名。您需要将cURL参数保存到文件中,并将文件名传递给$zip->addFile。如果您查看PHP文档,它需要的是一个文件名,而不是字符串:

要添加的文件的路径。

你需要做的事情是:

代码语言:javascript
复制
$temp_file = './temp_file.txt';
file_put_contents($temp_file, $download_file);
$file_added = $zip->addFile($temp_file);

// Delete after use
unlink($temp_file);
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/14414715

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