Oracle 11g:考虑以下两个CASE语句
搜索案件
with null_table as (select null as null_set from dual )
select
case
when (null_set is null) then 'NULL INDEED'
else 'NOTNULL?'
end as AM_I_NULL_OR_NOT
from null_table单例
with null_table as (select null as null_set from dual )
select
case null_set
when (null) then 'NULL INDEED'
else 'NOTNULL?'
end as AM_I_NULL_OR_NOT
from null_table搜索的案例按预期计算null_set,但是简单的案例似乎没有这样做。
问题:如何在null_set上执行简单的案例评估?
为什么这个简单的案例会像它那样评估呢?
发布于 2013-01-17 19:09:07
在Oracle中,不能将null与使用=运算符进行比较。
例如:
select * from dual where null = null; -- No result
select * from dual where 1 = 1; -- gives a result因此,您可以做的是使用NVL将null替换为另一个值:
with null_table as (select null as null_set from dual )
select
case nvl(null_set,'X')
when 'X' then 'NULL INDEED'
else 'NOTNULL?'
end as AM_I_NULL_OR_NOT
from null_table(确保您的字段永远不能等于示例中的值X)。
https://stackoverflow.com/questions/14386266
复制相似问题