假设我有一个浮点数。我想要找到小于X的最大数字,并且可以无损地存储在浮点数中。
IEEE标准IIRC说,您可以通过将浮点数转换为int表示,减去一个表示,然后将其转换回浮点数。
(编辑:对于不是NaN或inf的正数,这是正确的。对于负数,您必须添加。请参阅Rawling's answer获取更多信息。)
要在表示之间进行更改,我只知道C# (cast)操作符,它会截断,这不是我想要的。
在C#中有办法做到这一点吗?
发布于 2013-01-11 12:36:53
下面是如何简单地将float转换为int,更改它,然后将其转换回float
float myFloat = 10.3f;
// Get the bytes making up the float
byte[] bytes = BitConverter.GetBytes(myFloat);
// Make an int out of them
int myInt = BitConverter.ToInt32(bytes, 0);
// Change it
myInt--;
// Get the bytes making up the int
bytes = BitConverter.GetBytes(myInt);
// Make a float out of them
myFloat = BitConverter.ToSingle(bytes, 0);
// gives 10.2999992 or soBitConverter甚至为64位等价物内置了此功能:
double myDouble = 10.3;
long myLong = BitConverter.DoubleToInt64Bits(myDouble);
myLong--;
myDouble = BitConverter.Int64BitsToDouble(myLong); // gives 10.2999999...然而,正如Peter Ruderman所指出的,简单地减少底层int并不能可靠地给出最小的float。
特别是,对于负数,您需要增加整数,以使浮点数更负。对于float 0,下一个最小的int实际上对应于NaN,所以这里需要一个特例。
这里有几个函数,我把它们拼凑在一起,这些函数一般都能处理这些情况;它看起来也能理智地在大数和正/负无穷大之间传播!我使用了不安全的转换来减少代码长度,但是如果您愿意,可以坚持上面的字节转换:
static unsafe float Increment(float f)
{
int val = *(int*)&f;
if (f > 0)
val++;
else if (f < 0)
val--;
else if (f == 0)
return float.Epsilon;
return *(float*)&val;
}
static unsafe float Decrement(float f)
{
int val = *(int*)&f;
if (f > 0)
val--;
else if (f < 0)
val++;
else if (f == 0)
return -float.Epsilon; // thanks to Sebastian Negraszus
return *(float*)&val;
}正如Jeppe所指出的,您可能也想
if (float.IsNaN(f)) return f;启动每个函数,这样就不会意外地增加或减少NaN并给出一个数字。float.PositiveInfinity或.NegativeInfinity检查输入,因为从数学上讲,在增量/减少的情况下,输入应该保持不变。发布于 2013-01-11 14:16:17
这里有一个库例程,nexttowardf(x, -INFINITY);。
如果你想用你自己的代码来完成它,你可以使用本机(在IEEE 754浮点操作中,而不需要访问浮点编码或组件),如下所示(在C中)。
提供了两个版本,一个在每种情况下都使用一个低于正常值的值(在某些处理器上可能比较慢),另一个版本只在输入较小的情况下才使用低于正常值(但它有分支)。+无穷大不支持作为输入,尽管可以通过简单的测试添加支持。这是为double编写的,但是对float的更改很简单。
如果定义了CompileMain,它还包括一个测试程序。
#include <float.h>
#include <math.h>
/* Return the next floating-point value before the finite value q.
This was inspired by Algorithm 3.5 in Siegfried M. Rump, Takeshi Ogita, and
Shin'ichi Oishi, "Accurate Floating-Point Summation", _Technical Report
05.12_, Faculty for Information and Communication Sciences, Hamburg
University of Technology, November 13, 2005.
*/
double NextBefore(double q)
{
// SmallestPositive is the smallest positive floating-point number.
static const double SmallestPositive = DBL_EPSILON * DBL_MIN;
/* Scale is .625 ULP, so multiplying it by any significand in [1, 2)
yields something in [.625 ULP, 1.25 ULP].
*/
static const double Scale = 0.625 * DBL_EPSILON;
#if 0
/* This version has a branch but uses subnormal values only if q is so
small that q * Scale is subnormal.
*/
double increment = fabs(q)*Scale;
if (0. == increment)
return q - SmallestPositive;
return q - increment;
#else
/* This version uses a subnormal, SmallestPositive, in each case.
This might cause poor performance on some processors.
*/
return q - fmax(SmallestPositive, fabs(q)*Scale);
#endif
}
#if defined CompileMain
#include <stdio.h>
#include <stdlib.h>
#define NumberOf(a) (sizeof (a) / sizeof *(a))
int main(void)
{
int status = EXIT_SUCCESS;
static const struct { double in, out; } cases[] =
{
{ -INFINITY, -INFINITY },
{ -0x1.fffffffffffffp1023, -INFINITY },
{ -0x1.ffffffffffffep1023, -0x1.fffffffffffffp1023 },
{ -0x1.ffffffffffffdp1023, -0x1.ffffffffffffep1023 },
{ -0x1.ffffffffffffcp1023, -0x1.ffffffffffffdp1023 },
{ -0x1.0000000000003p1023, -0x1.0000000000004p1023 },
{ -0x1.0000000000002p1023, -0x1.0000000000003p1023 },
{ -0x1.0000000000001p1023, -0x1.0000000000002p1023 },
{ -0x1.0000000000000p1023, -0x1.0000000000001p1023 },
{ -0x1.fffffffffffffp1022, -0x1.0000000000000p1023 },
{ -0x1.fffffffffffffp1, -0x1.0000000000000p2 },
{ -0x1.ffffffffffffep1, -0x1.fffffffffffffp1 },
{ -0x1.ffffffffffffdp1, -0x1.ffffffffffffep1 },
{ -0x1.ffffffffffffcp1, -0x1.ffffffffffffdp1 },
{ -0x1.0000000000003p1, -0x1.0000000000004p1 },
{ -0x1.0000000000002p1, -0x1.0000000000003p1 },
{ -0x1.0000000000001p1, -0x1.0000000000002p1 },
{ -0x1.0000000000000p1, -0x1.0000000000001p1 },
{ -0x1.fffffffffffffp-1022, -0x1.0000000000000p-1021 },
{ -0x1.ffffffffffffep-1022, -0x1.fffffffffffffp-1022 },
{ -0x1.ffffffffffffdp-1022, -0x1.ffffffffffffep-1022 },
{ -0x1.ffffffffffffcp-1022, -0x1.ffffffffffffdp-1022 },
{ -0x1.0000000000003p-1022, -0x1.0000000000004p-1022 },
{ -0x1.0000000000002p-1022, -0x1.0000000000003p-1022 },
{ -0x1.0000000000001p-1022, -0x1.0000000000002p-1022 },
{ -0x1.0000000000000p-1022, -0x1.0000000000001p-1022 },
{ -0x0.fffffffffffffp-1022, -0x1.0000000000000p-1022 },
{ -0x0.ffffffffffffep-1022, -0x0.fffffffffffffp-1022 },
{ -0x0.ffffffffffffdp-1022, -0x0.ffffffffffffep-1022 },
{ -0x0.ffffffffffffcp-1022, -0x0.ffffffffffffdp-1022 },
{ -0x0.0000000000003p-1022, -0x0.0000000000004p-1022 },
{ -0x0.0000000000002p-1022, -0x0.0000000000003p-1022 },
{ -0x0.0000000000001p-1022, -0x0.0000000000002p-1022 },
{ -0x0.0000000000000p-1022, -0x0.0000000000001p-1022 },
{ +0x1.fffffffffffffp1023, +0x1.ffffffffffffep1023 },
{ +0x1.ffffffffffffep1023, +0x1.ffffffffffffdp1023 },
{ +0x1.ffffffffffffdp1023, +0x1.ffffffffffffcp1023 },
{ +0x1.0000000000004p1023, +0x1.0000000000003p1023 },
{ +0x1.0000000000003p1023, +0x1.0000000000002p1023 },
{ +0x1.0000000000002p1023, +0x1.0000000000001p1023 },
{ +0x1.0000000000001p1023, +0x1.0000000000000p1023 },
{ +0x1.0000000000000p1023, +0x1.fffffffffffffp1022 },
{ +0x1.0000000000000p2, +0x1.fffffffffffffp1 },
{ +0x1.fffffffffffffp1, +0x1.ffffffffffffep1 },
{ +0x1.ffffffffffffep1, +0x1.ffffffffffffdp1 },
{ +0x1.ffffffffffffdp1, +0x1.ffffffffffffcp1 },
{ +0x1.0000000000004p1, +0x1.0000000000003p1 },
{ +0x1.0000000000003p1, +0x1.0000000000002p1 },
{ +0x1.0000000000002p1, +0x1.0000000000001p1 },
{ +0x1.0000000000001p1, +0x1.0000000000000p1 },
{ +0x1.0000000000000p-1021, +0x1.fffffffffffffp-1022 },
{ +0x1.fffffffffffffp-1022, +0x1.ffffffffffffep-1022 },
{ +0x1.ffffffffffffep-1022, +0x1.ffffffffffffdp-1022 },
{ +0x1.ffffffffffffdp-1022, +0x1.ffffffffffffcp-1022 },
{ +0x1.0000000000004p-1022, +0x1.0000000000003p-1022 },
{ +0x1.0000000000003p-1022, +0x1.0000000000002p-1022 },
{ +0x1.0000000000002p-1022, +0x1.0000000000001p-1022 },
{ +0x1.0000000000001p-1022, +0x1.0000000000000p-1022 },
{ +0x1.0000000000000p-1022, +0x0.fffffffffffffp-1022 },
{ +0x0.fffffffffffffp-1022, +0x0.ffffffffffffep-1022 },
{ +0x0.ffffffffffffep-1022, +0x0.ffffffffffffdp-1022 },
{ +0x0.ffffffffffffdp-1022, +0x0.ffffffffffffcp-1022 },
{ +0x0.0000000000004p-1022, +0x0.0000000000003p-1022 },
{ +0x0.0000000000003p-1022, +0x0.0000000000002p-1022 },
{ +0x0.0000000000002p-1022, +0x0.0000000000001p-1022 },
{ +0x0.0000000000001p-1022, +0x0.0000000000000p-1022 },
};
for (int i = 0; i < NumberOf(cases); ++i)
{
double in = cases[i].in, expected = cases[i].out;
double observed = NextBefore(in);
printf("NextBefore(%a) = %a.\n", in, observed);
if (! (observed == expected))
{
printf("\tError, expected %a.\n", expected);
status = EXIT_FAILURE;
}
}
return status;
}
#endif // defined CompileMainhttps://stackoverflow.com/questions/14278248
复制相似问题