Ctypes获取窗口位置

Question

在Python中使用Ctypes可以获得记事本窗口的位置吗？

Python 3.8, OS: Windows 10.

我试过这段代码，但它没有给出窗口的位置：

import ctypes
user32 = ctypes.windll.user32
handle = user32.FindWindowW(None, u'test - Notepad')
rect = ctypes.wintypes.RECT()
ff=ctypes.windll.user32.GetWindowRect(handle, ctypes.pointer(rect))
print(rect)
print(ff)

它分别给出了以下输出：

<ctypes.wintypes.RECT object at 0x0000029358dc05c0>
1

Answer 1

wintypes.RECT没有实现__repr__，所以它显示一个通用的对象/地址描述。您可以打印各个字段：

import ctypes
from ctypes import wintypes
user32 = ctypes.windll.user32
handle = user32.FindWindowW(None, 'Untitled - Notepad')
rect = wintypes.RECT()
ff=ctypes.windll.user32.GetWindowRect(handle, ctypes.pointer(rect))
print(rect.left,rect.top,rect.right,rect.bottom)
print(ff)

153 188 1214 1157
1

或者，您可以在子类中定义__repr__。下面是一个经过完全类型检查和错误检查的版本：

import ctypes
from ctypes import wintypes as w

def errcheck(result,func,args):
    if result is None or result == 0:
        raise ctypes.WinError(ctypes.get_last_error())
    return result

# wintypes.RECT doesn't know how to display itself,
# so make a subclass that does.
class Rect(w.RECT):
    def __repr__(self):
        return f'Rect(left={self.left},top={self.top},right={self.right},bottom={self.bottom})'

user32 = ctypes.WinDLL('user32',use_last_error=True)
user32.FindWindowW.argtypes = w.LPCWSTR,w.LPCWSTR
user32.FindWindowW.restype = w.HWND
user32.GetWindowRect.argtypes = w.HWND,ctypes.POINTER(Rect)
user32.GetWindowRect.restype = w.BOOL
user32.GetWindowRect.errcheck = errcheck

if __name__ == '__main__':
    handle = user32.FindWindowW(None, 'Untitled - Notepad')
    if handle:
        rect = Rect()
        user32.GetWindowRect(handle,ctypes.byref(rect))
        print(rect)
    else:
        print('window not found')

Rect(left=153,top=188,right=1214,bottom=1157)