扫描可用wifi，检测特定最强的Wifi SSID以启动XML活动布局。

Question

我需要通过扫描最强大的Wifi来启动一个活动来定位我当前的位置。我只想找到那栋楼里的三个地方。因此，如果我目前在任何这些地点附近，我将点击一个按钮，以扫描最强的可用Wifi启动一个活动。

1. 我要扫描一栋楼里可用的Wifi。
2. 得到三个最强的信号。
3. 然后检测这3种最强信号的SSID是否与我想要定位的特定SSID相同。
4. 如果我的SSID是最强的3种信号之一，那么应用程序将启动一个xml布局活动，

到目前为止，我已经有了扫描最强可用的Wifi的编码。但是当检测到最强的特定的Wifi SSID时，我不知道如何启动一个活动。我不需要有关Wifi的信息，只是为了启动我的活动布局，有我的信息。

目前，我正在使用下面的代码来扫描来自这里的最强的Wifi信号

WiFiDemo.java

public class WiFiDemo extends Activity implements OnClickListener {
private static final String TAG = "WiFiDemo";
WifiManager wifi;
BroadcastReceiver receiver;

TextView textStatus;
Button buttonScan;

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // Setup UI
    textStatus = (TextView) findViewById(R.id.textStatus);
    buttonScan = (Button) findViewById(R.id.buttonScan);
    buttonScan.setOnClickListener(this);

    // Setup WiFi
    wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);

    // Get WiFi status
    WifiInfo info = wifi.getConnectionInfo();
    textStatus.append("\n\nWiFi Status: " + info.toString());

    // List available networks
    List<WifiConfiguration> configs = wifi.getConfiguredNetworks();
    for (WifiConfiguration config : configs) {
        textStatus.append("\n\n" + config.toString());
    }

    // Register Broadcast Receiver
    if (receiver == null)
        receiver = new WiFiScanReceiver(this);

    registerReceiver(receiver, new IntentFilter(
            WifiManager.SCAN_RESULTS_AVAILABLE_ACTION));
    Log.d(TAG, "onCreate()");
}

@Override
public void onStop() {
    unregisterReceiver(receiver);
}

public void onClick(View view) {
    Toast.makeText(this, "On Click Clicked. Toast to that!!!",
            Toast.LENGTH_LONG).show();

    if (view.getId() == R.id.buttonScan) {
        Log.d(TAG, "onClick() wifi.startScan()");
        wifi.startScan();
    }
} }

WiFiScanReceiver.java

      public class WiFiScanReceiver extends BroadcastReceiver {
        private static final String TAG = "WiFiScanReceiver";
        WiFiDemo wifiDemo;

      public WiFiScanReceiver(WiFiDemo wifiDemo) {
        super();
        this.wifiDemo = wifiDemo;
      }

      @Override
      public void onReceive(Context c, Intent intent) {
        List<ScanResult> results = wifiDemo.wifi.getScanResults();
        ScanResult bestSignal = null;
        for (ScanResult result : results) {
          if (bestSignal == null
              || WifiManager.compareSignalLevel(bestSignal.level, result.level) < 0)
            bestSignal = result;
        }

        String message = String.format("%s networks found. %s is the strongest.",
            results.size(), bestSignal.SSID);
        Toast.makeText(wifiDemo, message, Toast.LENGTH_LONG).show();

        Log.d(TAG, "onReceive() message: " + message);
      }

    }

Answer 1

您只需要从onReceive开始您的活动。除非我不理解你的问题，否则你只需要启动你的活动。由于接收方的onReceive上有上下文，所以只需要startActivity()

启动onReceive BroadcastReceiver中的活动

 @Override
    public void onReceive(Context context, Intent intent) {
        //start activity
        Intent i = new Intent();
        i.setClassName("com.test", "com.test.MainActivity");
        i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        context.startActivity(i);
    }

不要忘记在你的清单中为它定义一个适当的过滤器。http://developer.android.com/reference/android/content/BroadcastReceiver.html