我需要一个查询的帮助。我有多个食堂,每个食堂都有多餐饭,每顿饭都有多个MealPicks。
虽然我不知道这个MealPick模型是否是个好主意,因为我需要显示今天挑选了多少次饭,所以我需要时间戳来进行这个查询。
class Meal < ActiveRecord::Base
def todays_picks
meal_picks.where(["created_at >= ? AND created_at < ?", Date.today.beginning_of_day, Date.today.end_of_day])
end
end之前,我只有一个meal_picked_count计数器在餐中,我增加了increment_counter方法。
好的,现在我需要为每个食堂展示一顿MealPicks最多的饭菜,我在控制台里玩了一遍,尝试了一些类似Canteen.find(1).meals.maximum("meal_picks.count")的东西,但这显然是行不通的,因为它不是一个专栏。
有什么想法吗?
发布于 2012-12-12 20:56:05
canteen.meals.max {|m| m.meal_picked_count}发布于 2012-12-12 21:33:16
你可以这样做:
MealPick.joins(:meal => :canteen)
.where("canteens.id = ?", 1)
.order("count_all DESC")
.group(:meal_id)
.count它将返回这样的有序散列:
{ 200 => 25 }在那里,200将是餐id,25将是计数。
更新
对于感兴趣的人,我开始玩这个游戏,看看是否可以使用ActiveRecord的子查询来提供比我之前想出的更有意义的信息。我现在拥有的是:
class Meal < ActiveRecord::Base
belongs_to :canteen
has_many :meal_picks
attr_accessible :name, :price
scope :with_grouped_picks, ->() {
query = <<-QUERY
INNER JOIN (#{Arel.sql(MealPick.counted_by_meal.to_sql)}) as top_picks
ON meals.id = top_picks.meal_id
QUERY
joins(query)
}
scope :top_picks, with_grouped_picks.order("top_picks.number_of_picks DESC")
scope :top_pick, top_picks.limit(1)
end
class MealPick < ActiveRecord::Base
belongs_to :meal
attr_accessible :user
scope :counted_by_meal, group(:meal_id).select("meal_id, count(*) as number_of_picks")
scope :top_picks, counted_by_meal.order("number_of_picks DESC")
scope :top_pick, counted_by_meal.order("number_of_picks DESC").limit(1)
end
class Canteen < ActiveRecord::Base
attr_accessible :name
has_many :meals
has_many :meal_picks, through: :meals
def top_picks
@top_picks ||= meals.top_picks
end
def top_pick
@top_pick ||= top_picks.first
end
end这使我可以这样做:
c = Canteen.first
c.top_picks #Returns their meals ordered by the number of picks
c.top_pick #Returns the one with the top number of picks假设我想按挑选的次数来订购所有的饭菜。我可以这么做:
Meal.includes(:canteen).top_picks #Returns all meals for all canteens ordered by number of picks.
Meal.includes(:canteen).where("canteens.id = ?", some_id).top_picks #Top picks for a particular canteen
Meal.includes(:canteen).where("canteens.location = ?", some_location) #Return top picks for a canteens in a given location由于我们使用的是联接、分组和服务器端计数,所以不需要加载整个集合来确定挑选计数。这有点灵活,而且可能更有效率。
https://stackoverflow.com/questions/13847971
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