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社区首页 >问答首页 >SwingUtilities.convertPoint()返回负值

SwingUtilities.convertPoint()返回负值
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Stack Overflow用户
提问于 2012-12-07 08:00:03
回答 2查看 1.8K关注 0票数 4

在另一个具有复杂的JPanels结构和大量代码的项目中,我面临着这个问题。

在这里我有一个下面的片段

代码语言:javascript
复制
Point point = label.getLocation();
Point point2 = SwingUtilities.convertPoint(label.getParent(), point, panel);

在动态选择标签和面板的地方,JLabel应该是JPanel的大.子级。

那么,为什么问题是,在什么情况下,如果源和目标有子父关系,SwingUtilities.convertPoint() 可以返回负值?这有可能吗?

此代码演示了负坐标问题,但panel22不是label的父级。

代码语言:javascript
复制
import java.awt.BorderLayout;
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Point;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.SwingUtilities;

public class NegativeLocation {
    public static void main(String[] args) {
        new NegativeLocation();
    }

    public NegativeLocation() {
        EventQueue.invokeLater(new Runnable() {
            @Override
            public void run() {
                JFrame frame = new JFrame();
                frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
                frame.setLayout(new BorderLayout());

                JPanel panel1 = new JPanel() {
                     @Override
                     public Dimension getPreferredSize() {
                         return new Dimension(600, 400);
                     }
                };

                JPanel panel21 = new JPanel() {
                    @Override
                    public Dimension getPreferredSize() {
                        return new Dimension(300, 400);
                    }
                };
                panel1.add(panel21);

                JPanel panel22 = new JPanel() {
                    @Override
                    public Dimension getPreferredSize() {
                        return new Dimension(300, 400);
                    }
                };
                panel1.add(panel22);

                JPanel panel3 = new JPanel() {
                    @Override
                    public Dimension getPreferredSize() {
                        return new Dimension(300, 400);
                    }
                };
                panel21.add(panel3);

                JLabel label = new JLabel("Label");
                panel3.add(label);

                frame.getContentPane().add(panel1);
                frame.setPreferredSize(new Dimension(600, 400));

                frame.pack();
                frame.setLocationRelativeTo(null);
                frame.setVisible(true);

                Point point = label.getLocation();
                Point point2 = SwingUtilities.convertPoint(label.getParent(), point, panel21);
                Point point3 = SwingUtilities.convertPoint(label.getParent(), point, panel22);

                System.out.println(point2);
                System.out.println(point3);
            }
        });
    }
}

所以输出是

代码语言:javascript
复制
java.awt.Point[x=134,y=10]
java.awt.Point[x=134,y=-395]

UPD:基本上,我需要得到label相对于panel21的位置。我如何修改这一行来实现它呢?

代码语言:javascript
复制
Point point = label.getLocation();
Point point2 = SwingUtilities.convertPoint(label.getParent(), point, panel21);
EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2012-12-07 08:45:32

举下面的例子..。

代码语言:javascript
复制
public class TestLocation01 {

    public static void main(String[] args) {
        new TestLocation01();
    }

    public TestLocation01() {
        EventQueue.invokeLater(new Runnable() {
            @Override
            public void run() {
                try {
                    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
                } catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
                }

                JPanel outter = new JPanel(new BorderLayout());
                outter.setBorder(new CompoundBorder(new LineBorder(Color.RED), new EmptyBorder(10, 10, 10, 10)));
                JPanel inner = new JPanel(new GridBagLayout());
                inner.setBorder(new CompoundBorder(new LineBorder(Color.BLUE), new EmptyBorder(10, 10, 10, 10)));
                JLabel label = new JLabel("Testing");
                inner.add(label);
                outter.add(inner);

                JLabel below = new JLabel("Below");

                JFrame frame = new JFrame("Test");
                frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
                frame.setLayout(new BorderLayout());
                frame.add(outter);
                frame.add(below, BorderLayout.SOUTH);
                frame.setSize(200, 200);
                frame.setLocationRelativeTo(null);
                frame.setVisible(true);

                System.out.println("lable.location: " + label.getLocation());
                System.out.println("label to inner: " + SwingUtilities.convertPoint(label, new Point(0, 0), inner));
                System.out.println("label to outter: " + SwingUtilities.convertPoint(label, new Point(0, 0), outter));
                System.out.println("label.parent to inner: " + SwingUtilities.convertPoint(label.getParent(), new Point(0, 0), inner));
                System.out.println("label.parent to outter: " + SwingUtilities.convertPoint(label.getParent(), new Point(0, 0), outter));
                System.out.println("label to frame: " + SwingUtilities.convertPoint(label, new Point(0, 0), frame));
                System.out.println("label.getParent to frame: " + SwingUtilities.convertPoint(label.getParent(), new Point(0, 0), frame));
                System.out.println("outter to label: " + SwingUtilities.convertPoint(outter, new Point(0, 0), label));
                System.out.println("label to below: " + SwingUtilities.convertPoint(label, new Point(0, 0), below));
                System.out.println("below to label: " + SwingUtilities.convertPoint(below, new Point(0, 0), label));
            }
        });
    }        
}

,它生成(在我的系统上)以下输出

代码语言:javascript
复制
lable.location: java.awt.Point[x=65,y=62]
label to inner: java.awt.Point[x=65,y=62]
label to outter: java.awt.Point[x=76,y=73]
label.parent to inner: java.awt.Point[x=0,y=0]
label.parent to outter: java.awt.Point[x=11,y=11]
label to frame: java.awt.Point[x=76,y=95]
label.getParent to frame: java.awt.Point[x=11,y=33]
outter to label: java.awt.Point[x=-76,y=-73]
label to below: java.awt.Point[x=76,y=-89]
below to label: java.awt.Point[x=-76,y=89]

如果将label作为源组件传递,则根据label与要转换到的坐标空间之间的关系获得相对位置。如果我传递label的父空间,我将使用父坐标空间,这必然会产生不正确的结果。

如果你看看labelbelow之间的关系,你会得到负面的结果是有意义的,因为labelbelow的上方和右边

票数 4
EN

Stack Overflow用户

发布于 2012-12-07 08:14:45

对我来说这是正确的行为。想象一下。主面板包含一个具有位置x=0 y=100的子面板。如果将主面板0,0点转换为子面板,它将返回0,-100。事实上,哪个组件是哪个组件的父组件并不重要。逻辑是添加(所有减法)所有转换()调用,这些调用在父级呈现子文件时应用于图形。

票数 7
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/13759112

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