无效“row.names”长度

Question

我试图使用TraMineR(Version1.8.4) seqdef-funciton来定义序列对象，但是我总是收到这样的错误消息，这对我来说是没有意义的: error in row.names<-.data.frame(*tmp*，value = value)：无效的'row.names‘长度

我的代码输入是：

sample.sts <- seqdef(sample, var=c("jan2005", "feb2005", "mar2005", "apr2005", "may2005", 
"jun2005", "jul2005", "aug2005", "sep2005", "oct2005", "nov2005", "dec2005"),  
alphabet=c("Employee (full-time)", "Employee (part-time)", 
"Self-employed (full-time)", "Self-employed (part-time)", "unemployed", "Retired", 
"Student", "Other inactive", "Compulsory military service"), 
states=c("EF", "EP", "SF", "SP", "UE", "RE", "ST", "IA", "MS"), id="pidc")

数据框架“示例”如下所示：

    pidc           jan2005   feb2005    ...    dec2005   sex   edufirst   age05   
--------------------------------------------------------------------------    
1.  150163920001         .         .    ...         .    1          5      62   
2.  211518110003         .         .    ...         .    2          2      17   
3.  170295160002         .         .    ...         .    2          1      47   
4.  240386550002         2         2    ...         2    2          2      50   
5.  320099920001         .         .    ...         .    1          3      38   
--------------------------------------------------------------------------    
6.  200167850001         .         .    ...         .    1          5      39  
7.  340401190002         6         6    ...         6    1          3      61  
8.  180501260002         .         .    ...         .    1          3      29  
9.  230083560001         .         .    ...         .    1          3      61  
10. 240335270002         3         3    ...         3    2          3      30  

整个产出显示：

好了！在州代码中找到“-”字符，不推荐 >找到序列数据中的缺失值('NA') >制备3266序列 >用'%‘编码空元素，用'*’编写缺失值 好了！指数序列: 1,2,3，. >状态编码： 字母长标号 1名雇员(全职) EF 2名雇员(兼职) EP 3自营职业者(全职) 4自雇(兼职) SP 5个失业UE UE 6退休RE 7学生圣圣 8其他不活跃的IA IA 9义务兵役制 > 3266序列在数据集中 >最小/最大序列长度: 12/12 row.names<-.data.frame中的Fehler (*tmp*，value = value)： 无效“row.names”长度

在没有"-“的状态重新贴上标签后，我重新试了一次，这不影响错误。也许，有人能帮我，知道是什么导致了这个错误？

Answer 1

seqdef的"id“参数应该是包含每个序列一个条目的向量(即。id向量的长度应等于序列数)。尝试使用id=as.character(示例$pid)。您也可以尝试id=sample$pid (没有as.character)

sample.sts <- seqdef(sample, var=c("jan2005", "feb2005", "mar2005", "apr2005", "may2005", "jun2005", "jul2005", "aug2005", "sep2005", "oct2005", "nov2005", "dec2005", "jan2006", "feb2006", "mar2006", "apr2006", "may2006",  "jun2006", "jul2006", "aug2006", "sep2006", "oct2006", "nov2006", "dec2006",  "jan2007", "feb2007", "mar2007", "apr2007", "may2007",  "jun2007", "jul2007", "aug2007", "sep2007", "oct2007", "nov2007", "dec2007", "jan2008", "feb2008", "mar2008", "apr2008", "may2008", "jun2008", "jul2008", "aug2008", "sep2008", "oct2008", "nov2008", "dec2008"),  alphabet=c("Employee (full-time)", "Employee (part-time)", "Self-employed (full-time)", "Self-employed (part-time)", "unemployed", "Retired", "Student", "Other inactive", "Compulsory military service"), states=c("EF", "EP", "SF", "SP", "UE", "RE", "ST", "IA", "MS"), d=as.character(sample$pid))

数据中的状态和字母表参数之间存在一些不匹配，因为"-“被”替换为“。您可能应该更改字母表参数(尝试使用seqstatl函数找出数据中存在标签的状态)。