我很难理解为什么我从未点击下面的GETNEARCALLBACK函数。逻辑是这样的:
INITIALIZEINITIALIZE愉快地执行并调用GETSTATIONSGETSTATIONS使用GETNEARESTSTAIONS作为回调函数执行AJAX请求,web服务器以JSON格式响应数据库查询的结果。GETNEARESTSTAIONS接受结果并使用GETNEARCALLBACK作为回调函数创建Google距离矩阵请求GETNEARCALLBACK。我认为我对Google的使用是正确的,因为如果我不从AJAX请求中调用GETNEARESTSTATIONS,它就会正确执行。
函数初始化(){ GETPOSITION();DRAWMAP();GETADDR();GETSTATIONS();}
var xmlhttp;
function GETSTATIONS() {
if(window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
} else {
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = GETNEARESTSTATION();
xmlhttp.open("GET", "final.php", true);
xmlhttp.send();
}
var STATIONLIST;
function GETNEARESTSTATION() {
if(xmlhttp.readyState == 4 && xmlhttp.status == 200) {
STATIONLIST = eval("(" + xmlhttp.responseText + ")");
var LAT = parseFloat(document.getElementById("LATITUDE").value);
var LON = parseFloat(document.getElementById("LONGITUDE").value);
var latlng = new google.maps.LatLng(LAT, LON);
var destinationA = STATIONLIST[0].ADDRESS;
var service = new google.maps.DistanceMatrixService();
service.getDistanceMatrix({
origins: [latlng],
destinations: [destinationA],
travelMode: google.maps.TravelMode.DRIVING,
unitSystem: google.maps.UnitSystem.IMPERIAL,
avoidHighways: false,
avoidTolls: false
}, GETNEARCALLBACK);
}
}
function GETNEARCALLBACK(response, status) {
if(status == google.maps.DistanceMatrixStatus.OK) {
var destinations = response.destinationAddresses;
var results = response.rows[0].elements;
for(var j = 0; j < results.length; j++) {
var element = results[j];
document.getElementById("STATIONADDR").innerHTML = parseFloat(element.distance.value) + " " + response.destinationAddresses[j];
}
}
}发布于 2012-12-03 04:06:49
需要函数变量,而不是函数返回值。
//xmlhttp.onreadystatechange = GETNEARESTSTATION(); //error
xmlhttp.onreadystatechange = GETNEARESTSTATION; https://stackoverflow.com/questions/13676863
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