如何使我的方法add_friend在rake :seed中工作

Question

我在推特克隆人上学习查尔斯·马克斯·伍德的教程，飞人。当我启动rake：undefined method friendships时，我有一个错误的add_friend，我试图通过rake :add_friend任务添加好友，方法add_friend是在用户模型中定义的。但是，我需要帮助来定义方法友谊，这样任务就可以为您的帮助提供大量的.Thank。

这里是db/seeds.rb文件

require 'faker'
require 'populator'

User.destroy_all

10.times do
  user = User.new
  user.username = Faker::Internet.user_name
  user.email = Faker::Internet.email
  user.password = "test"
  user.password_confirmation = "test"
  user.save
end


User.all.each do |user|  
  Flit.populate(5..10) do |flit|
    flit.user_id = user.id
    flit.message = Faker::Lorem.sentence
  end

  3.times do
    User.add_friend(User.all[rand(User.count)])
  end
end

，这是用户文件.

class User < ActiveRecord::Base
  # new columns need to be added here to be writable through mass assignment
  attr_accessible :username, :email, :password, :password_confirmation

  attr_accessor :password
  before_save :prepare_password

  validates_presence_of :username
  validates_uniqueness_of :username, :email, :allow_blank => true
  validates_format_of :username, :with => /^[-\w\._@]+$/i, :allow_blank => true, :message => "should only contain letters, numbers, or .-_@"
  validates_format_of :email, :with => /^[-a-z0-9_+\.]+\@([-a-z0-9]+\.)+[a-z0-9]{2,4}$/i
  validates_presence_of :password, :on => :create
  validates_confirmation_of :password
  validates_length_of :password, :minimum => 4, :allow_blank => true

  has_many :flits, :dependent => :destroy

  has_many :friendships
  has_many :friends, :through => :friendships



  def self.add_friend(friend)
    friendship = friendships.build(:friend_id => friend.id)
      if !friendship.save
        logger.debug "User '#{friend.email}' already exists in the user's friendship list."
      end
  end

  # login can be either username or email address
  def self.authenticate(login, pass)
    user = find_by_username(login) || find_by_email(login)
    return user if user && user.password_hash == user.encrypt_password(pass)
  end

  def encrypt_password(pass)
    BCrypt::Engine.hash_secret(pass, password_salt)
  end

  private

  def prepare_password
    unless password.blank?
      self.password_salt = BCrypt::Engine.generate_salt
      self.password_hash = encrypt_password(password)
    end
  end
end

friendship.rb

class Friendship < ActiveRecord::Base
  attr_accessible :friend_id, :user_id

  belongs_to :user
  belongs_to :friend, :class_name => 'User'
  validates_uniqueness_of :friend_id, :scope => :user_id
  validates_presence_of :user_id, :friend_id
end

Answer 1

我认为您要做的是在实例user上调用user，而不是在类User上调用

3.times do
  user.add_friend(User.all[rand(User.count)])
end

另外，add_friend方法应该是实例方法，而不是类方法，因此不需要self

def add_friend(friend)
  friendship = friendships.build(:friend_id => friend.id)
    if !friendship.save
      logger.debug "User '#{friend.email}' already exists in the user's friendship list."
    end
end

Answer 2

应该将此方法定义为类方法，而不是实例方法：

  def self.add_friend(friend)
    friendship = friendships.build(:friend_id => friend.id)
      if !friendship.save
        logger.debug "User '#{friend.email}' already exists in the user's friendship list."
      end
  end