使用两个条件获得计数的嵌套查询

Question

我有三张桌子，

tbl_1-
ip  |isp    |infection
----------------------
1   |aaaa   |malware
2   |bbbb   |malware
3   |cccc   |ddos
3   |cccc   |trojan
4   |dddd   |ddos

tbl_2-
ip  |isp    |infection
----------------------
1   |aaaa   |malware
3   |cccc   |ddos
4   |dddd   |trojan
5   |eeee   |trojan
6   |ffff   |other

tbl_3-
ip  |isp    |infection
----------------------
1   |aaaa   |ddos
6   |ffff   |
2   |bbbb   |other

我需要得到如下结果，

result-
ip  |isp    |infection  |ipCount    |ispCount   |infectionCount
--------------------------------------------------------------
1   |aaaa   |malware    |3          |3          |2
1   |aaaa   |ddos       |3          |3          |1
2   |bbbb   |other      |2          |2          |1
2   |bbbb   |malware    |2          |2          |1
3   |cccc   |ddos       |3          |3          |2
3   |cccc   |trojan     |3          |3          |1
4   |dddd   |ddos       |2          |2          |1
4   |dddd   |trojan     |2          |2          |1
5   |eeee   |trojan     |1          |1          |1
6   |ffff   |other      |2          |2          |1
6   |ffff   |           |2          |2          |1

ipCount, ispCount -> count of matching ip and isp
    eg-there are 3 records with ip = 1 and isp = aaaa

infectionCount -> count of matching infections per ip and isp
    eg-there are 2 infections that says malware where ip = 1 and isp = aaaa

我想我需要一个嵌套的查询，但是我不知道如何用两个条件来计数；您能帮忙吗？

编辑：我尝试过的代码，

SELECT ip, isp, infection, count(ip), count(isp), count(infection)
FROM (

SELECT ip, isp, infection
FROM tbl_1
UNION ALL
SELECT ip, isp, infectionType
FROM tbl_2
UNION ALL
SELECT ip, isp, infection
FROM tbl_3
)x

GROUP BY ip, isp, infection

但是它没有给出我想要的结果，因为我不知道如何在一个查询中进行两种类型的计数

Answer 1

您需要对列infection和(ip & ipc)进行不同的分组，然后使用以下子查询连接它们：

SELECT t1.ip, t1.isp, t2.infection, t1.ipc, t1. ispc, t2.incount
FROM
    (SELECT ip, isp, infection, COUNT(ip) as ipc, COUNT(isp) as ispc
    FROM (
       SELECT ip, isp, infection
       FROM tbl1
       UNION ALL
       SELECT ip, isp, infection
       FROM tbl2
       UNION ALL
       SELECT ip, isp, infection
       FROM tbl3
       )x
     GROUP BY ip, isp) t1
JOIN
    (SELECT ip, isp, infection, COUNT(infection) as incount
     FROM (
       SELECT ip, isp, infection
       FROM tbl1
       UNION ALL
       SELECT ip, isp, infection
       FROM tbl2
       UNION ALL
       SELECT ip, isp, infection
       FROM tbl3
       )x
    GROUP BY ip, isp,  infection)t2
ON t1.ip = t2.ip
ORDER BY ip, isp, infection Desc

参见此SQLFiddle

注：我认为您想要的输出是错误的，因为：

1. 在Table3中，ip=6没有infection，但是它在输出中
2. 在您的输出中缺少infection other (而不是malware)

Answer 2

可以将所有表合并在一起，然后根据特定列对列和进行分组。

SELECT ip, isp, infection, COUNT(ip) AS ipcount, COUNT(isp) AS ispcount, COUNT(infection) AS infectioncount
FROM
  (
    SELECT ip, isp, infection
    FROM table_1
    UNION ALL
    SELECT ip, isp, infection
    FROM table_2
    UNION ALL
    SELECT ip, isp, infection
    FROM table_3
  )
GROUP BY ip, isp, infection
ORDER BY ip, isp, infection;