我正在处理一个WPF应用程序,在其中我需要动态生成两个组框,其中有一个单选按钮、文本框和一个组合框。嗯,我遇到了一个棘手的情况,在两个组框中,价值观需要不同。
我有两个xaml文件PCM2PDMView.xaml和PCM2PDMWidgetView.xaml & viewmodel类。
PCM2PDMView.xaml:
<UserControl.Resources>
<DataTemplate x:Key="PCM2PDMDataTemplate">
<WrapPanel>
<TextBlock Text="{Binding Description}" Margin="5,5,0,0"/>
<local:PCM2PDMWidgetView Margin="5,10,5,5"/>
</WrapPanel>
</DataTemplate>
</UserControl.Resources>
<Grid Style="{DynamicResource styleBackground}" >
<ItemsControl ItemTemplate="{StaticResource PCM2PDMDataTemplate}" ItemsSource="{Binding PCM2PDMWidgets}">
<ItemsControl.ItemsPanel>
<ItemsPanelTemplate>
<WrapPanel />
</ItemsPanelTemplate>
</ItemsControl.ItemsPanel>
</ItemsControl>
</Grid>PCM2PDMWidgetView.xaml:
<Grid>
<GroupBox Height="Auto" HorizontalAlignment="Stretch" Margin="5" Name="groupBox1" VerticalAlignment="Stretch" Width="Auto">
<Grid>
<Grid Grid.Row="1">
<RadioButton Grid.Column="1" Content="Port B" Command="{Binding PortCommand}" IsChecked="{Binding PortCheck}" Height="20" Width="60" HorizontalAlignment="Center" Margin="0,0,0,0" Name="PCM2PDMEnableRadioBtn" VerticalAlignment="Center" />
</Grid>
<Grid Grid.Row="2">
<ComboBox Grid.Column="1" Height="20" ItemsSource="{Binding PortModeList}" SelectedItem="{Binding SelectedPortModeList, Mode=OneWayToSource}" SelectedIndex="0" HorizontalAlignment="Center" Margin="0,0,0,0" Name="PortModeCombo" VerticalAlignment="Center" Width="110" />
</Grid>
<Grid Grid.Row="3">
<ToggleButton Grid.Column="0" Content="Soft Reset" Height="25" Width="105" HorizontalAlignment="Center" Margin="0,0,0,0" Name="SoftResetRadioBtn" VerticalAlignment="Center" />
<ToggleButton Grid.Column="1" Command="{Binding PCM2PDMEnableCommand}" IsChecked="{Binding PCM2PDMCheck}" Content="PCM2PDM Enable" Height="25" Width="110" HorizontalAlignment="Center" Margin="0,0,0,0" Name="PCM2PDMRadioBtn" VerticalAlignment="Center" />
</Grid>
<Grid Grid.Row="4">
<TextBox Height="25" IsReadOnly="True" Text="{Binding MemAddPoint}" Margin="0" Name="SetRead" />
</Grid>
</Grid>
</GroupBox>
</Grid>PCM2PDmViewModel.cs:
public ObservableCollection<PCM2PDMWidgetViewModel> PCM2PDMWidgets { get; set; }
public PCM2PDMViewModel()
{
PCM2PDMWidgets = new ObservableCollection<PCM2PDMWidgetViewModel>();
PCM2PDMWidgets.Add(new PCM2PDMWidgetViewModel { Description = "PCM2PDM 0", ID = 0 });
PCM2PDMWidgets.Add(new PCM2PDMWidgetViewModel { Description = "PCM2PDM 1", ID = 1 });
}这将生成两个组框,并在其中包含关联的UI控件。
PCM2PDMWidgetViewModel.cs:
public ObservableCollection<string> _PortModeList = _PortModeList = new ObservableCollection<string>();
_PortModeList.Add("Normal"); //Adding in Constructor
_PortModeList.Add("Mode 1 - PCM + PDM");
_PortModeList.Add("Mode 2 - PDM only");
public ObservableCollection<string> PortModeList
{
get { return _PortModeList; }
set
{
_PortModeList = value;
OnPropertyChanged("PortModeList");
}
}
private string _selectedPortModeList;
public string SelectedPortModeList
{
get { return _selectedPortModeList; }
set
{
_selectedPortModeList = value;
OnPropertyChanged("SelectedPortModeList");
}
}
public string Description {get; set;}
public int ID {get; set;}
public string MemAddPoint {get; set;}Requirement:
Grid.Row=1,您会发现一个名为Port B的无线电按钮,我的要求是在我的第一个组盒中有Port B,在第二个组框中有Port C。这两种功能(按钮单击方法)都是通用的,但名称必须不同。我们如何才能做到这一点?Normal和Mode 1 - PCM + PDM,在第二组盒中添加Normal、Mode 1 - PCM + PDM和Mode 2 - PDM Only。如何做到这一点?)Grid.Row=3,您将发现PCM2PDMEnable切换按钮。我希望这个切换按钮在我的第二个组框中可见,而不是在我的第一个组框中。我怎么能这么做?Grid.Row=4中的Textbox有一个textbox,其值为(例如0x5)。我需要将这个文本框的文本设置为Groupbox2的Groupbox 1中的0x5和textbox中的0x7。怎么做?(请帮助:)
发布于 2012-10-23 11:15:23
在"PCM2PDMWidgetViewModel“中创建一个属性,如"RadioButtonName”,在创建"PCM2PDMWidgetViewModel“实例时,将该属性设置为您想要的名称。像这样的东西
PCM2PDMWidgets.Add(new PCM2PDMWidgetViewModel { Description = "PCM2PDM 0", ID = 0, RadioButtonName = "Port B" });
PCM2PDMWidgets.Add(new PCM2PDMWidgetViewModel { Description = "PCM2PDM 1", ID = 1, RadioButtonName = "Port C" }); In PCM2PDMWidgetView XAML:
将单选按钮内容更改为绑定“Content=”{}“”
<Grid Grid.Row="1">
<RadioButton Grid.Column="1" Content="{Binding RadioButtonName}" Command="{Binding PortCommand}" IsChecked="{Binding PortCheck}" Height="20" Width="60" HorizontalAlignment="Center" Margin="0,0,0,0" Name="PCM2PDMEnableRadioBtn" VerticalAlignment="Center" />
</Grid>而不是在构造函数中添加以下元素。将它们作为参数作为一个列表发送给构造函数。
您的代码
_PortModeList.Add(“普通”);//添加构造器_PortModeList.Add(“模式1- PCM + PDM");_PortModeList.Add(”模式2-PDM“);
2的解
公共PCM2PDMWidgetViewModel(列表comboBoxItems) {foreach(comboBoxItems中的项目){_PortModeList.Add(项目);}
在创建"PCM2PDMWidgetViewModel“实例时,将列表作为构造函数参数发送(请参阅以下代码)
PCM2PDMWidgets.Add(new PCM2PDMWidgetViewModel (new List<string>{"Normal","Mode 1 - PCM + PDM"}) { Description = "PCM2PDM 0", ID = 0, RadioButtonName = "Port B" });
PCM2PDMWidgets.Add(new PCM2PDMWidgetViewModel(new List<string>{"Normal","Mode 1 - PCM + PDM","Mode 2"}) { Description = "PCM2PDM 1", ID = 1, RadioButtonName = "Port C" }); 为4
您可以用与radion按钮名相同的方式来修复这个问题。
为"MemAddPoint“属性设置值的方式与对描述和ID的设置相同。
For 3:
您必须在“可见性”类型的"PCM2PDMWidgetViewModel“中创建一个新属性,并将其绑定到togglebutton可见属性。在创建实例时设置属性值
https://stackoverflow.com/questions/13029083
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