这是一个基于求最大嵌套区间集的大小的问题。
有许多间隔,每个间隔由包含一个起点和一个结束点(si,ei)的对定义。如果i1和i2完全位于i1内部,则称为嵌套i2。示例:- (2,6)和(3,4)嵌套,因为(3,4)是(2,6)的一部分。类似地,k间隔i1、i2、i3....ik称为嵌套if,i2位于i1中,i3位于i2中,...and等等。从给定的间隔确定最大间隔集的大小,以便该集合中的所有间隔都能产生嵌套。
我是这样想的:-让我们用一个例如- (0,7) (0,5) (1,21) (1,9) (2,8) (2,4) (3,20) (4,16) (5,15) (6,21)排序,使ai-1<=ai & bi-1>=bi,而不是从第一个区间开始,我们开始一个链表。如果下一个间隔在一个区间内,我们沿着节点向下移动并遍历创建的图(主列表除外),..we在此图中存储最大级别节点的指针,新的间隔可以在该指针上适应。并在链接列表中进一步遍历,以查看当前间隔在谁下面。最后,我们有一个指向节点的指针,该节点必须附加当前间隔。并将此节点的级别与我们已有的最大级别进行比较……最大值的最终值是最大嵌套区间集的大小。
上述解决方案的复杂性可能是:- O(n(k+l) + nlogn)
我想这样很难,但我没有别的选择.如果有人有其他算法来解决它..。请张贴,因为我的算法将需要更长的时间来实现(很多数据结构).谢谢!
发布于 2014-04-24 05:59:52
编辑:一些问题的解决方案在http://codeforces.com/blog/entry/5541上发布,包括两个自称O(n lg n)的解决方案。然而,我认为O(n lg n)解不起作用。我在那一页上发表了评论,说明了原因。如果有人有O(n lg n)的解决方案,我很想听听。
二次解
这个问题可以用动态规划在O(n^2)时间内解决:
MaxNestedIntervals解决问题*注:步骤1可以在O(n lg n)时间内使用这里的解来完成:计算嵌套间隔的子O(n^2)算法?步骤2可以在O(n lg n)时间内完成,并使用任何基于最优比较的排序算法。也许有一种优化步骤3的方法,但我还没有找到它。
递归
MaxNestedIntervals(i) =
max {j = 0 to i-1} :
1 + MaxNestedIntervals(j) if interval i contains interval j
0 if interval i doesn't contain interval j基案例
MaxNestedIntervals(i) =
0 if interval i contains 0 intervals
1 if interval i contains 1 interval示例代码
import java.util.*;
public class MaxNestedIntervals {
public static void main(String[] args) {
Interval[] intervals = new Interval[10];
intervals[0] = new Interval(0, 7);
intervals[1] = new Interval(0, 5);
intervals[2] = new Interval(1, 21);
intervals[3] = new Interval(1, 9);
intervals[4] = new Interval(2, 8);
intervals[5] = new Interval(2, 4);
intervals[6] = new Interval(3, 20);
intervals[7] = new Interval(4,16);
intervals[8] = new Interval(5,15);
intervals[9] = new Interval(6,21);
int n = intervals.length;
AugmentedInterval[] augmentedIntervals = new AugmentedInterval[n];
for (int i = 0; i < n; i++) {
augmentedIntervals[i] = new AugmentedInterval(intervals[i]);
}
for (int i = 0; i < n; i++) {
AugmentedInterval outerInterval = augmentedIntervals[i];
for (int j = 0; j < n; j++) {
if (i == j) {
continue;
}
AugmentedInterval innerInterval = augmentedIntervals[j];
if (outerInterval.contains(innerInterval)) {
outerInterval.numContainedIntervals++;
if (outerInterval.childInterval == null) {
outerInterval.childInterval = innerInterval;
}
}
}
}
Arrays.sort(augmentedIntervals, new Comparator<AugmentedInterval>() {
public int compare(AugmentedInterval i, AugmentedInterval j) {
return i.numContainedIntervals - j.numContainedIntervals;
}
});
int maxNestedIntervals = 0;
AugmentedInterval parentInterval = null;
for (int i = 0; i < n; i++) {
AugmentedInterval currentInterval = augmentedIntervals[i];
if (currentInterval.numContainedIntervals == 0) {
currentInterval.maxNestedIntervals = 0;
} else if (currentInterval.numContainedIntervals == 1) {
currentInterval.maxNestedIntervals = 1;
} else {
int maxNestedIntervalsForCurrentInterval = 0;
for (int j = 0; j < i; j++) {
AugmentedInterval candidateNestedInterval = augmentedIntervals[j];
int maxNestedIntervalsForCurrentCandidate = candidateNestedInterval.maxNestedIntervals + 1;
if (currentInterval.contains(candidateNestedInterval) && maxNestedIntervalsForCurrentCandidate >= maxNestedIntervalsForCurrentInterval) {
maxNestedIntervalsForCurrentInterval = maxNestedIntervalsForCurrentCandidate;
currentInterval.childInterval = candidateNestedInterval;
}
}
currentInterval.maxNestedIntervals = maxNestedIntervalsForCurrentInterval;
if (maxNestedIntervalsForCurrentInterval >= maxNestedIntervals) {
maxNestedIntervals = maxNestedIntervalsForCurrentInterval;
parentInterval = currentInterval;
}
}
}
if (n == 0) {
System.out.println("The largest set of nested intervals is the empty set.");
} else if (maxNestedIntervals == 0) {
System.out.println("The largest set of nested intervals has 1 interval.\n");
System.out.println("That interval is:");
} else {
System.out.println("The largest set of nested intervals has " + (maxNestedIntervals + 1) + " intervals.\n");
System.out.println("Those intervals are:");
}
for (AugmentedInterval currentInterval = parentInterval; currentInterval != null; currentInterval = currentInterval.childInterval) {
System.out.println(currentInterval);
}
System.out.println();
}
private static class Interval implements Comparable<Interval> {
public int start = 0;
public int end = 0;
public Interval(int start, int end) {
this.start = start;
this.end = end;
}
public int size() {
return this.end - this.start;
}
public boolean contains(Interval other) {
return (this.start <= other.start && this.end >= other.end);
}
public int compareTo(Interval other) {
return this.size() - other.size();
}
public String toString() {
return "[" + this.start + ", " + this.end + "]";
}
}
private static class AugmentedInterval extends Interval {
public int numContainedIntervals = 0;
public int maxNestedIntervals = 0;
public AugmentedInterval childInterval = null;
public AugmentedInterval(Interval interval) {
super(interval.start, interval.end);
}
}
}https://stackoverflow.com/questions/12896156
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