下面的代码试图测试boost::mpl::or_和boost::mpl::and_的短路行为。
#include <vector>
#include <boost/mpl/eval_if.hpp>
#include <boost/mpl/identity.hpp>
#include <boost/mpl/or.hpp>
#include <boost/mpl/and.hpp>
#include <boost/type_traits/is_scalar.hpp>
// Dummy is forward declared and never defined
template <class T> class dummy;
// If T is a scalar evaluates to T without trying to compute the result of
// boost::mpl::is_scalar< dummy<T>, otherwise it fails at compile time.
template <class T>
class testOr
: public boost::mpl::eval_if<
boost::mpl::or_< boost::is_scalar<T>, boost::is_scalar< dummy<T> > >,
boost::mpl::identity<T>,
dummy<T>
>
{};
// If T is not a scalar evaluates to T without trying to compute the result of
// boost::mpl::is_scalar< dummy<T>, otherwise it should fail at compile time.
template <class T>
class testAnd
: public boost::mpl::eval_if<
// It appears that is_scalar< dummy<T> > is not instantiated and the operation
// evaluates to false
boost::mpl::and_< boost::is_scalar<T>, boost::is_scalar< dummy<T> > >,
dummy<T>,
boost::mpl::identity<T>
>
{};
int main() {
static_assert(boost::is_same< testOr< double >::type, double>::type::value,"Fails at compile time");
// The following line causes failures at compile time due to incomplete type definition
//static_assert(boost::is_same< testOr< std::vector<double> >::type, double>::type::value,"Fails at compile time");
static_assert(boost::is_same< testAnd< std::vector<double> >::type, std::vector<double> >::type::value,"Fails at compile time");
// The following should cause failure at compile time due to incomplete type definition, but works instead!
static_assert(boost::is_same< testAnd< double >::type , double >::type::value,"Fails at compile time");
return 0;
}虽然我预计由于类型定义不完整,这段代码在编译时会失败,但它实际上是有效的:
>icpc --version
icpc (ICC) 12.1.3 20120212
Copyright (C) 1985-2012 Intel Corporation. All rights reserved.
>icpc -gcc-name=gcc-4.5 -std=c++0x -o ex-4.0.x ex-4.0.cc所以,我想了解的是:
boost::mpl::or_ 和 boost::mpl::and_ 计算它们的参数的方式是否不一致?或者,最有可能的是,我无法捕捉到的代码中有错误吗?
发布于 2012-09-14 14:22:16
为什么您认为or_的第二个参数不会被计算?is_scalar可以与未定义的类型一起使用。
例如,在这种情况下,您也会得到您的错误。
// If T is not a scalar evaluates to T without trying to compute the result of
// boost::mpl::is_scalar< dummy<T>, otherwise it should fail at compile time.
template <class T>
class testAnd
: public boost::mpl::eval_if<
// It appears that is_scalar< dummy<T> > is not instantiated and the operation
// evaluates to false
boost::mpl::and_< boost::is_scalar<T>, boost::is_scalar< dummy<T> > >,
boost::mpl::identity<T>,
dummy<T>
>
{};因为boost::is_scalar<T>是真,但在您的情况下boost::is_scalar<dummy<T>>是假的,所以。
看。http://liveworkspace.org/code/a792e18ca16a0410a67a6eee8c550bd9
发布于 2012-09-14 14:35:57
您的想法有一个逻辑错误- ||将短路iif第一个参数评估为true。is_scalar<std::vector<double>>是false,这意味着需要计算第二个参数。相反,&&将短路iif,第一个论点是false,这就是上面所说的情况。
https://stackoverflow.com/questions/12426342
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