这方面的优化查询可以是什么？

Question

我一直在进行小的查询。有一个名为Table_Activities的表。

Table_Activities (Act_id，Date，Activity_name，description)。

我们需要从这产生一份报告。用户将从下拉列表中选择要生成报表的、月份、和年份。

我们需要按活动名称显示该月份和年度组的所有活动。

示例-用户选择6月和2012。

报告将是-

园艺

01/06/2012 - They have planted 100 trees.
14/06/2012 - something
27/06/2012 - something

训练

02/06/2012 - Detail description
15/06/2012 - something
28/06/2012 - something

我的问题是，用这种格式获取数据的mysql查询是什么？？

Answer 1

select `Date`,description from tm_activities 
where month(`Date`)='6' and year(`Date`)='2012' 
order by Activity_name,`date` 

若要返回您问题中所述的确切格式，请尝试如下：

select concat(if(actdate='',activity_name,date_format(actdate,'%d/%m/%y')),if(description<>'',concat(' - ',description),'')) as labelm from
(
(select ActDate,description,activity_name from tm_activities where month(ActDate)='6' and year(ActDate)='2012' 
) 
union all
(Select distinct '','',activity_name from tm_activities where month(ActDate)='6' and year(ActDate)='2012')
)m order by activity_name,actdate
;

SQL小提琴在这里。

产出如下：

Gardening
01/06/12 - They have planted 100 trees.
27/06/12 - Gar 2
Training
12/06/12 - Training 1
28/06/12 - Traning 2
30/06/12 - Traning 3

Answer 2

Select 
    DATE_FORMAT('date_column',"%D/%M/%Y") as `Date`,
    other_column  
from Table_Activities 
where Month(Date) = Month('2012-06-01')
AND Year(Date) = Year('2012-06-01')