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ubuntu中mysql中的存储过程
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Stack Overflow用户
提问于 2012-08-13 05:15:21
回答 1查看 1.7K关注 0票数 0

我在Window-7中用MySQL创建了存储过程。它在windows上成功运行。但是当我切换到Ubuntu时,它会在存储过程中出现错误。在windows上,我使用SQLyog创建存储过程。在Ubuntu上,我运行SQL脚本并调用那个存储过程,但是它会产生错误。下面是我的存储过程。

代码语言:javascript
复制
DELIMITER $$

USE `adserver`$$

DROP PROCEDURE IF EXISTS `getDaypartTimeDetail`$$

CREATE DEFINER=`root`@`localhost` PROCEDURE `getDaypartTimeDetail`
(currentDate DATE,noOfdays INT,cityId BIGINT)
BEGIN

DECLARE i INT;
DECLARE dateCnt INT;
SET dateCnt = 0;

DROP TEMPORARY TABLE IF EXISTS OnlyDate;
DROP TEMPORARY TABLE IF EXISTS AdvScheduleData;
CREATE TEMPORARY TABLE OnlyDate(dday DATE); 
CREATE TEMPORARY TABLE AdvScheduleData(dday BIGINT,daypartId INT,totalFile BIGINT,totalDur BIGINT); 

/* Generate Dates */
WHILE(dateCnt < noOfdays) DO
    SET i = 1;
    INSERT INTO OnlyDate(dday) VALUES (DATE_ADD(currentDate, INTERVAL dateCnt DAY));
SET dateCnt = dateCnt + 1;
END WHILE;

/* Insert all dayparts for all dates */ 
INSERT INTO AdvScheduleData (dday, daypartID) SELECT (UNIX_TIMESTAMP(dday)*1000), id FROM OnlyDate, daypart;
/* Update total files and duration */       
UPDATE AdvScheduleData SET 
    TotalFile =    (SELECT COUNT(advt_id) 
            FROM adv_schedule AdvSch
            INNER JOIN advertisement Adv ON Adv.id = AdvSch.advt_id
              WHERE AdvScheduleData.dday BETWEEN AdvSch.start_date AND AdvSch.end_date
              AND AdvSch.status = 2
              AND AdvSch.active = 1
              AND AdvSch.id IN (SELECT schedule_id FROM schedule_daypart 
               WHERE daypart_id = AdvScheduleData.daypartId )
              AND AdvSch.id IN (SELECT schedule_id FROM schedule_cities WHERE city_id = cityId)
              AND Adv.is_active = 1 
              AND Adv.is_deleted = 0
              AND Adv.status = 2 
              AND Adv.expiry_date >= AdvScheduleData.dday),
    totalDur =    (SELECT SUM(Adv.duration)
            FROM adv_schedule AdvSch
            INNER JOIN advertisement Adv ON Adv.id = ADVSCH.advt_id
              WHERE AdvScheduleData.dday BETWEEN AdvSch.start_date AND AdvSch.end_date
              AND AdvSch.status = 2
              AND AdvSch.active = 1
              AND AdvSch.id IN (SELECT schedule_id FROM schedule_daypart 
               WHERE daypart_id = AdvScheduleData.daypartId )
              AND AdvSch.id IN (SELECT schedule_id FROM schedule_cities WHERE city_id = cityId)
              AND Adv.is_active = 1 
              AND Adv.is_deleted = 0
              AND Adv.status = 2 
              AND Adv.expiry_date >= AdvScheduleData.dday);
SELECT * FROM AdvScheduleData;
END$$

DELIMITER ;

我在Ubuntu中得到的输出是

mysql> call getDaypartTimeDetail('2012-08-13',5,30534);错误1054 (42S22):on子句中未知列'ADVSCH.advt_id‘

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2012-08-13 06:02:38

表名和别名在Ubuntu中区分大小写。

因此,此引用提供了一个错误:

代码语言:javascript
复制
totalDur =    (SELECT SUM(Adv.duration)
        FROM adv_schedule AdvSch
        INNER JOIN advertisement Adv ON Adv.id = ADVSCH.advt_id

将其更改为AdvSch.advt_id

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/11928516

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