我需要使用子查询来命名查询中的列。我在SELECT部分中编写了一个带有子查询的语句,但是我得到了以下错误消息(从Codeigniter返回):
错误号: 1064 您的SQL语法出现错误;请检查与您的MySQL服务器版本对应的手册,以获得使用near‘的正确语法(从
product_selects中选择ps_id= '1'),在第1行选择psc_opt_2A
SELECT
`psc_opt_1` AS (SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '1'),
`psc_opt_2` AS (SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '2'),
`psc_opt_3` AS (SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '3'),
`psc_opt_4` AS (SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '4'),
`psc_opt_5` AS (SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '5')
FROM (`product_stock_control`)
WHERE `psc_prod_id` = '5'文件名: models/products_model.php 线路号码: 602
有什么不对吗?
发布于 2012-08-09 16:57:18
AS是一个列别名运算符,意味着您要选择这些变量作为标识符。不能使用运算符标识带有查询的变量。
参考:http://dev.mysql.com/doc/refman/5.0/en/problems-with-alias.html
相反,您需要反向使用别名操作符,如下所示:
SELECT
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '1') AS `psc_opt_1`,
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '2') AS `psc_opt_2`,
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '3') AS `psc_opt_3`,
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '4') AS `psc_opt_4`,
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '5') AS `psc_opt_5`
FROM (`product_stock_control`)
WHERE `psc_prod_id` = '5'理想情况下,您应该避免使用子查询(尤其是在本例中)来避免表锁定开销。
发布于 2012-08-09 16:58:20
正确格式是
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '1') As `psc_opt_1` 发布于 2012-08-09 16:59:01
你试过这个吗?
SELECT
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '1') as `psc_opt_1`,
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '2') as `psc_opt_2`,
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '3') as `psc_opt_3`,
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '4') as `psc_opt_4`,
(SELECT `ps_url_name` FROM `product_selects` WHERE `ps_id` = '5') as `psc_opt_5`
FROM (`product_stock_control`)
WHERE `psc_prod_id` = '5'https://stackoverflow.com/questions/11888279
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