SELECT users.mail, users.name FROM members
LEFT JOIN users ON (users.uid = members.uid) WHERE members.group = 27
AND members.uid NOT IN (SELECT subgroup_members.uid FROM subgroup_members
LEFT JOIN subgroups ON (subgroups.id = subgroup_members.sid)
LEFT JOIN users on (users.uid = subgroup_members.uid) WHERE subgroups.oid = 27 AND subgroup_members.leader = 1)此查询返回组中并非子组领导的所有成员。
members表显示哪个userid(uid)属于group(group),subgroup_members表显示哪些用户属于subgroup(sid)。领导力在subgroup_members表的领导列中用'1‘表示。
我正在努力弄清楚如何让一个小组的所有成员返回,他们并不是一个分组的唯一领导人,我现在很困惑。
所以,与subgroup_members.leader = 1不同,我需要确定它是否是唯一的值
发布于 2012-07-19 16:54:50
研究如何使用GROUP BY来分离唯一的索引。
Documentation:https://dev.mysql.com/doc/refman/5.5/en/group-by-modifiers.html
https://stackoverflow.com/questions/11565621
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