HttpTransportSE。呼叫错误

Question

我是学生和新的安卓，我有一个Webservice (WFC C#)，当我在Visual测试时，它是可以的。我的android代码：

    String NAMESPACE="http://tempuri.org/";
    String METHOD_NAME="Hello"; // method public string Hello() [WCF]
    String SOAP_ACTIONS=NAMESPACE+"/"+METHOD_NAME;
    String URL="http://localhost:8732/BookInformationHost/BookService/"; // host Service 
    SoapObject request=new SoapObject(NAMESPACE, METHOD_NAME);
    SoapSerializationEnvelope envelope=new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet=true;
    envelope.encodingStyle=SoapSerializationEnvelope.ENC;
    envelope.setOutputSoapObject(request);
    HttpTransportSE transp=new HttpTransportSE(URL);
    try
    {
        Toast.makeText(getApplicationContext(), "Try 1", Toast.LENGTH_SHORT).show();
        transp.call(SOAP_ACTIONS, envelope);
        Toast.makeText(getApplicationContext(), "Try 2", Toast.LENGTH_SHORT).show();
        Object result=(Object)envelope;
        Toast.makeText(getApplicationContext(), result.toString(), Toast.LENGTH_SHORT).show();

    }catch(Exception ex)
    {
        Toast.makeText(getApplicationContext(), "Hello_Error", Toast.LENGTH_SHORT).show();
    } 

吐司表演(“尝试1")和"Hello_Error”。所以我需要做些什么才能从Webservice上的函数字符串中获得字符串。非常感谢！

Answer 1

String URL="http://localhost:8732/BookInformationHost/BookService/"; // host Service 

安卓不明白，所以localhost要么把10.0.2.2或者你的系统的IP地址。然后再试..。还发布异常日志，您从中得到了什么。