我有一个名为客户端的下表,其列和值如下:
+--------+-----------+--------------+----------------+
| uid | client_id | client_input | input_value |
+--------+-----------+--------------+----------------+
| 1 | 22 | City | Seattle |
+--------+-----------+--------------+----------------+
| 2 | 45 | City | Ojai |
+--------+-----------+--------------+----------------+
| 3 | 22 | State | OR |
+--------+-----------+--------------+----------------+
| 4 | 45 | State | CA |
+--------+-----------+--------------+----------------+
| 5 | 65 | City | Orlando |
+--------+-----------+--------------+----------------+
| 6 | 74 | State | AB |
+--------+-----------+--------------+----------------+
| 7 | 65 | State | FL |
+--------+-----------+--------------+----------------+
| 8 | 12 | City | Los Angeles |
+--------+-----------+--------------+----------------+
| 9 | 12 | State | CA |我需要PHP/MySql查询,它将列出位于'CA‘状态的input_value列中的所有城市。显然,公共标识符是 client_id ,它始终是匹配的,因为如果客户端位于‘洛杉矶’中,那么在input_value列中包含'CA'值的行中也有相同的client_id。这个表有超过800万行,任何快速执行的均衡器都会受到高度赞赏。
我的大脑被炸了,截止日期快到了,不能改变桌子的设计,需要帮助,请!
发布于 2012-06-12 18:39:22
SELECT *
FROM table AS t1 INNER JOIN table AS t2 ON t1.client_id = t2.client_id
WHERE t1.client_input = 'City' AND t2.client_input = 'State' AND t2.input_value = 'CA'注:,这可能需要一些调整,并可能是优化的。但它应该能让你开始冷静下来。
发布于 2012-06-12 18:42:31
我没有测试这个查询。但是这个或类似的查询应该可以工作。我首先使用了两个子查询来避免不可缺少的联接。第一个子查询过滤器用于状态'CA‘,第二个子查询用于城市。如果您想要按州为所有城市创建一个表,请从子查询a中删除'CA‘子句。
SELECT b.input_value AS city, a.input_value AS state
FROM
(SELECT client_id, input_value
FROM tablename
WHERE input_value = 'CA'
AND client_input = 'State')
AS a,
(SELECT client_id, input_value
FROM tablename
WHERE client_input = 'City')
AS b
WHERE a.client_id = b.client_id发布于 2012-06-12 18:46:53
SELECT distinct
t2.Input_Value as City
from
YourTable t1
JOIN YourTable t2
on t1.client_ID = t2.Client_ID
AND t2.client_input = 'City'
where
t1.client_input = 'State'
AND t1.Input_Value = 'CA'我会有两个索引。(Client_Input,Input_Value)和(Client_ID,Client_Input,Input_Value)
https://stackoverflow.com/questions/11002565
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