Java XStream CannotResolveClassException

Question

我试图使用XStream将XML文件解析为对象，但我得到了这个异常：

线程“主”com.thoughtworks.xstream.mapper.CannotResolveClassException:服务器中的

异常在com.thoughtworks.xstream.mapper.DefaultMapper.realClass(DefaultMapper.java:56) at com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:30) at com.thoughtworks.xstream.mapper.DynamicProxyMapper.realClass(DynamicProxyMapper.java:55) .

这里是我的XML:

  <servers>
    <server>
      <ip>10.196.113.27</ip> 
    </server>
    <server>
      <ip>10.196.113.31</ip> 
    </server>
  </servers>

这里是我的代码：

public class ServerIP {
    private String ip;

    public String getIp() {
        return ip;
    }

    public void setIp(String ip) {
        this.ip = ip;
    }
}

public class ServerHandler {

    private String fileName = "servers.xml";
    private String path = "J:\\workspace\\LOG730\\src\\Q3\\";
    private XStream xstream = new XStream(new DomDriver());

    public void readFromXML() {
        try {
            FileInputStream fis = new FileInputStream(path + fileName);
            ServerIP server = (ServerIP) xstream.fromXML(fis, new ServerIP());
            System.out.println("Host: " + server.getIp());
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }
    }

异常由以下内容触发：

    ServerHandler serverHandler = new ServerHandler();
    serverHandler.readFromXML();

Answer 1

尝试添加类服务器以保存ServerIP实例，并添加以下行：

xstream.alias("servers", Servers.class);
xstream.alias("server", ServerIP.class);

在这里，您可以找到一个关于别名的简单教程：http://x-stream.github.io/alias-tutorial.html

Answer 2

@XStreamAlias("server")
public class ServerIP {
    private String ip;

    public String getIp() {
        return ip;
    }

    public void setIp(String ip) {
        this.ip = ip;
    }
}

很抱歉答案不完整，我在做完之前就心不在焉地发表了。与此同时，特格指着这个方向。