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社区首页 >问答首页 >如何使用EdDSA/Ed448签名算法重新生成私钥?

如何使用EdDSA/Ed448签名算法重新生成私钥?
EN

Stack Overflow用户
提问于 2020-09-21 18:40:22
回答 1查看 432关注 0票数 1

下面是我生成密钥对的方式:

代码语言:javascript
复制
var keyPairGenerator = KeyPairGenerator.getInstance("Ed448");
keyPairGenerator.initialize(448, SecureRandom.getInstanceStrong());
var keyPair = keyPairGenerator.generateKeyPair();
var privateKey = keyPair.getPrivate();
var publicKey = keyPair.getPublic();
byte[] privateKeyBytes = privateKey.getEncoded();
byte[] publicKeyBytes = publicKey.getEncoded();

然而,当我再次尝试重新生成密钥时,我得到了一个异常:

代码语言:javascript
复制
var keyFactory = KeyFactory.getInstance("EdDSA");
var edECPoint = byteArrayToEdPoint(publicKeyBytes);
var edECPublicKeySpec = new EdECPublicKeySpec(new NamedParameterSpec("Ed448"), edECPoint);
var publicKey = keyFactory.generatePublic(edECPublicKeySpec);
var edECPrivateKeySpec = new EdECPrivateKeySpec(new NamedParameterSpec("Ed448"), privateKeyBytes);
var privateKey = keyFactory.generatePrivate(edECPrivateKeySpec); // generatePrivate() throws exception

异常堆栈跟踪:

代码语言:javascript
复制
Exception in thread "main" java.security.spec.InvalidKeySpecException: java.security.InvalidKeyException: key length is 73, key length must be 57
    at jdk.crypto.ec/sun.security.ec.ed.EdDSAKeyFactory.engineGeneratePrivate(EdDSAKeyFactory.java:129)
    at java.base/java.security.KeyFactory.generatePrivate(KeyFactory.java:390)
    at io.fouad.Main.main(Main.java:48)
Caused by: java.security.InvalidKeyException: key length is 73, key length must be 57
    at jdk.crypto.ec/sun.security.ec.ed.EdDSAPrivateKeyImpl.checkLength(EdDSAPrivateKeyImpl.java:84)
    at jdk.crypto.ec/sun.security.ec.ed.EdDSAPrivateKeyImpl.<init>(EdDSAPrivateKeyImpl.java:61)
    at jdk.crypto.ec/sun.security.ec.ed.EdDSAKeyFactory.generatePrivateImpl(EdDSAKeyFactory.java:171)
    at jdk.crypto.ec/sun.security.ec.ed.EdDSAKeyFactory.engineGeneratePrivate(EdDSAKeyFactory.java:127)
    ... 2 more

下面是我从OpenJDK repo复制的一些实用程序

代码语言:javascript
复制
private static EdECPoint byteArrayToEdPoint(byte[] arr)
{
    byte msb = arr[arr.length - 1];
    boolean xOdd = (msb & 0x80) != 0;
    arr[arr.length - 1] &= (byte) 0x7F;
    reverse(arr);
    BigInteger y = new BigInteger(1, arr);
    return new EdECPoint(xOdd, y);
}

private static void reverse(byte [] arr)
{
    int i = 0;
    int j = arr.length - 1;
    
    while(i < j)
    {
        swap(arr, i, j);
        i++;
        j--;
    }
}

private static void swap(byte[] arr, int i, int j)
{
    byte tmp = arr[i];
    arr[i] = arr[j];
    arr[j] = tmp;
}
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2020-09-21 19:35:57

由于privateKey.getEncoded(实例将为EdDSAPrivateKeyImpl类型)将返回PKCS8格式的密钥,因此您应该使用PKCS8EncodedKeySpec

代码语言:javascript
复制
var keyFactory = KeyFactory.getInstance("EdDSA");
var pkcs8EncodedKeySpec = new PKCS8EncodedKeySpec(privateKeyBytes);
var privateKey = keyFactory.generatePrivate(pkcs8EncodedKeySpec);

否则,您将不得不自己解开序列并获得PrivateKey (这是OctetString),如RFC5958-section2中所述。然后你可以使用EdECPrivateKeySpec

票数 3
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/63990653

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